Search found 2 matches
I missed something in your explanation
I missed something in your answer but still
2*(2*3*4*5...50) != (2*4*6*8...100)
But I am still unsure of the correct answer. My guess is that the lowest prime should be in the smallest range.
Tried to pop the numbers into a spreadsheet and the result was too large to get a meaningful answer.
- by katwilson09
Tue Nov 28, 2006 2:38 pm- Forum: Problem Solving
- Topic: GMATprep - quant Q indicative of real exam?
- Replies: 10
- Views: 13439
hmmm...don't think so
I do not think that you are correct with the reasoning
h(100) = 2*k(50)
2*(2*4*6*....50) != (2*4*6*....50*52*54*.....98*100)
That is like saying 2*50! == 100! which is incorrect
- by katwilson09
Tue Nov 28, 2006 1:54 pm- Forum: Problem Solving
- Topic: GMATprep - quant Q indicative of real exam?
- Replies: 10
- Views: 13439