Search found 14 matches


I think the answer should be A

RT = 960 ---given

They say if the train traveled 12 mph slower it would have taken 20 hrs

so R * 20 = 960

so R = 48

But actual R = 12 mph slower so R = 48 + 12 = 60

B is insuff

Please comment

by llewellyn27

Sun Jun 29, 2008 6:44 am
Forum: Data Sufficiency
Topic: Rate: Average Speed of Traveling Train from A to B
Replies: 5
Views: 2279

atlantic

Im really confised with this 4C2 etc.

can you please explain further

by llewellyn27

Sat Jun 28, 2008 3:39 pm
Forum: Problem Solving
Topic: two hard ps questions
Replies: 5
Views: 1396

range in May = 15000
Lowest in May = 4500
therefore highest in may = 19500

Range in June = 16500
Lowest in June = 6100
Higest in june = 22600

Therefore range for all cars sold = 22600-4500 = 18,100

by llewellyn27

Sat Jun 28, 2008 3:03 pm
Forum: Problem Solving
Topic: Last Minute GMATprep PS question
Replies: 3
Views: 1639

I think the answer is 6

using the eqn 3n+4 (Let n = 1,2,3,4,5,6,7)

By process of elimination the answer is 6

Ex:

3*1 + 4 = 7
3*2 +4 = 10(Divisible by 5)
3*4 + 4 = 16 (Divisible by 4 and 8)

and so on till u get only 6 remaining


TOOK ME 2 MINS

by llewellyn27

Thu Jun 12, 2008 2:07 pm
Forum: Problem Solving
Topic: I need explanation for 1000 PS question
Replies: 6
Views: 4304

can u expand on this formula.

Have not seen it in a while

by llewellyn27

Wed Jun 11, 2008 6:42 pm
Forum: Problem Solving
Topic: Joining sides of a pentagon to form trianges
Replies: 3
Views: 2262

Sorry for the typo in the previous post

in choice D, If n is even then k cannot be odd

ex: n = 2 then k = 200

by llewellyn27

Wed Jun 11, 2008 6:17 pm
Forum: Problem Solving
Topic: integer problem
Replies: 5
Views: 3503

I think the answer is E

because the factors of 400 are 2^4 5^2.

So if n is odd
N = 5 or n = 25

Therefore k has to be even multiple of 2

In the case of D

N could be odd and K could still be even
Ex: n = 1 , k = 400

Comments Welcome

by llewellyn27

Wed Jun 11, 2008 6:15 pm
Forum: Problem Solving
Topic: integer problem
Replies: 5
Views: 3503

Easy way to solve this is by plugging in numbers We know that a hexagon is made up of 6 Equilateral triangles Assume s = length of 1 side So perimeter = 6s Let P= 36 (divisible by 6) So s = 6 Diagonal is formed by the sides of 2 of the 6 Eq triangles in the figure so Diagonal is 12 Input p =36 in th...

by llewellyn27

Tue Jun 10, 2008 3:20 pm
Forum: Problem Solving
Topic: hexagon problem
Replies: 4
Views: 4032

Is the Answer 5/8 Assume Days had 20 boxes/ worker and had 10 workers. Total boxes by Days = 200 Therefore Nights loaded 3/4 * 20 = 15 boxes per worker And Nights had 4/5 * 10 = 8 workers Total boxes by nights = 120 Fraction of boxes loaded by Days as part of whole = Part / whole = 200/320 = 5/8 Ple...

by llewellyn27

Tue Jun 10, 2008 1:58 pm
Forum: Problem Solving
Topic: OG 138
Replies: 6
Views: 2965

Based on the formula for a series from a previous post An = A1 + (n-1)*d The 10th and units place are changed. So the resulting numbers would be 130 and 40 (Original numbers were 310 and 400) So now we have to find the numbers between 40 and 130 that are divisible by 3 The last number before 130 tha...

by llewellyn27

Tue Jun 10, 2008 1:45 pm
Forum: Problem Solving
Topic: How many three-digit integers between 310 and 400? help...
Replies: 13
Views: 8804

Not understanding the 1st statement
Please explain how it is insufficient?

by llewellyn27

Thu Jun 05, 2008 2:30 pm
Forum: Data Sufficiency
Topic: I think there's a mistake...
Replies: 4
Views: 1646

Netigen

I did it the same way

M = Y2-Y1 / X2-X1

Macth up the answer that you get with slope given in the stem.

If they match then the line passes thru the point. If not then it does not pass thru

by llewellyn27

Thu Jun 05, 2008 12:36 pm
Forum: Data Sufficiency
Topic: Coordinate Geomatry
Replies: 15
Views: 10178

is the second sweater 25% off or does the sweater cost 25%

Depending

The answer could be 140

by llewellyn27

Tue Jun 03, 2008 3:31 pm
Forum: Problem Solving
Topic: GMAT PS
Replies: 5
Views: 2545

Easy way to solve this problem is to plug in numbers Assume A = 10 and B = 5 A1 = ? and B1 = 10 (given a 100% increase) The ratio stays the same. So, A^2/ B = 100/5 A1^2 / B1 = A1^2/10 Solve for A1 which comes to 10* sqrt2 % Increase = (A1-A)/A * 100 = (sqrt2 -1) * 100 = 41% increase

by llewellyn27

Tue Jun 03, 2008 1:12 pm
Forum: Problem Solving
Topic: GMATPrep (rate)
Replies: 8
Views: 1784