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Congrats. I hope if you are planning to go for top 5 B-Schools (HSW+), they wont look at q48 as a weakness. Could you please point me to EMPOWER and how much does it cost for QUANT ? I have started reading for GMAT a month ago having scored a 720(Q44, V45) 6 years back ( yes 6 long years!!!) So any ...
why we can't do simple percentage without doing LCM. Please let me know.
If we take 100 people in the organization
Women # = 30
Married Man # = 3/8 of 100 = 37.5
Unmarried Man # = 100 - 30 - 37.5 = 32.5
and it becomes clear.
step 1: Look at the options. The smallest one is A) 29 Now can we have two three digit integres whose difference is 3 ? i.e N - M = 29 ? Step 2: what can be last digit of N and M to get a result of 9 ? n can be XY0 and M can be AB1 Step 2 : now can XY - (A(B+ 1 form Carry over) = 2 Step 3 X80 - X51 ...
Hi Ms. Anderson,
Thanks a lot for replying. Are you talking about MN state university? Please let me know.
Thanks and Regards,
Hi Ms. Blackman, I completed my GMAT journey with a not so stellar performance. It would be so kind of you if you could answer my questions after taking a brief look at my profile. Work Experience : 1. 5 years Indian Information Technology Company 2. Out of those 5 years 1 year in India, 6 months in...
the statement 1 says value of 1/n = 0.n.....
which can happen only if n =3 hence suff
stmt 2 says
value of 1/n = o.?n....
which can happen for n = 3 or n =6 hence Insuff
For 1 the number could be x = 5n + 1 = 5k +3 now depending on value of n these two expression can be odd or even i.e put n = 1 n=2 and so remainder can be 0 or 1. Hence A is Insuff but for 2 the expression 10j +1 will always be odd as 10j is always even hence remainder will always be 1 when divided ...
Hope this one will help. So basically you have to find a number which is of the form number == multiple of 6 +1 == multiple of 5 now multiple of 6 has a pattern when it comes to unit digit 6 2 8 4 0 | 6 2 8 4 0| 6 2 ... the only way you can get a multiple of 5 from this pattern is wen you add 1 to 4...
No stmt 2 is not
let the number be
XYZ where Z !=0
for Z+4 if Z<=5 Y remains as it is i.e Y could be 2 as given
if Z>5 tens digit Y becomes Y+1 i.e Y could be 1.
IMO it is A.
as stmt 1 can only be satisfied when
largest lot has 35 items.
any other way it is not possible.
Stmt 2. smallest one having 10 can lead to multiple situation
or 10+15+45 etc hence Insuff
the inequality becomes
is a2 +b2+a>0
we know a2 and b2 is always >0
hence question is asking is a>0 ?
that is what stmt 2 says.