## Search found 83 matches

this is a good time to refresh even myself on the exponent rules:

(a^m)^2 = a^(2m)

(ab)^2 = a^2 * b^2

(a+b)^2 = a^2 + 2ab + b^2

etc.

You did such a good job up until applying this rule, I hate to see hard earned points escape us...

- by VP_RedSoxFan

Thu Jul 31, 2008 12:34 pm- Forum: Problem Solving
- Topic: Exponents
- Replies:
**4** - Views:
**1204**

B-school reapplicants will tell you that the schools keep scores on file for 5 years (that is, when you re-apply, they say don't worry about sending scores again unless they've changed). Take the offer and send them since you'll do well ;) and you can save $28 a pop later since you'll be applying fo...

- by VP_RedSoxFan

Thu Jul 31, 2008 10:03 am- Forum: GMAT Strategy
- Topic: Selecting Score Recepients
- Replies:
**4** - Views:
**1121**

Congrats on the good score! The practice tests you get from signing up the exam are indeed the very best, most accurate exams out there. I bet you'd be surprised at how many people do well with little or no preparation. They go to Wharton and Stanford and work for hedge funds :). For someone coming ...

- by VP_RedSoxFan

Thu Jul 31, 2008 9:58 am- Forum: GMAT Strategy
- Topic: help! gmat in 3 weeks, varying practice scores
- Replies:
**1** - Views:
**1038**

In my experience, the OG questions are similar. By the same token, so are the questions from the test prep books as well. I'd hesitate to get anyone's anecdotal claims that one is harder than another. I would just try to learn as much as possible from them and get ready for test day. Hopefully that ...

- by VP_RedSoxFan

Thu Jul 31, 2008 9:53 am- Forum: Problem Solving
- Topic: Does any know...
- Replies:
**1** - Views:
**892**

This is a classic average problem where we don't know all of the individual elements, but can infer what we need from the information given. If the new average is $75 and it is 50% more than before, it must have been $50 for the 5 people contributing before John. If the average for the 5 was 50 befo...

- by VP_RedSoxFan

Thu Jul 31, 2008 9:46 am- Forum: Problem Solving
- Topic: averages
- Replies:
**2** - Views:
**1382**

I think the answer is D as well. r = v because they are interior angles created when two parallel lines are cut by another line. pepeprepa is right about that, it is a standard geometry rule you'll need on exam day. Therefore, for r = y, then y = v. If the whole thing is a square y = v when they are...

- by VP_RedSoxFan

Thu Jul 31, 2008 9:28 am- Forum: Problem Solving
- Topic: 3 Triangles
- Replies:
**9** - Views:
**1785**

I think this one has been answered before, but I'll help out anyway: The first thing I'd do is turn the 2^28 into 4^14, giving you 4^17 - 4^14. Then, I'd factor our the 4^14 leaving me with 4^14(4^3 - 1) I know the prime factors represented by 4^14 will just be 28 2's. So as long as I get something ...

- by VP_RedSoxFan

Thu Jul 31, 2008 9:20 am- Forum: Problem Solving
- Topic: Prime factor of big numbers?
- Replies:
**3** - Views:
**1874**

The best way to handle a problem like this, I think, is to do a quick example to understand the function F. F(8) = 4 {7,5,3,1}. Therefore, pick any prime, say 11. F(11) = 10 {10, 9,8,7,6,5,4,3,2,1} which makes sense because the prime number, by definition, doesn't share any positive common factors w...

- by VP_RedSoxFan

Thu Jul 31, 2008 9:17 am- Forum: Problem Solving
- Topic: Function Q
- Replies:
**1** - Views:
**1046**

- by VP_RedSoxFan

Thu Jul 31, 2008 9:09 am- Forum: Problem Solving
- Topic: Addition Problem (GPREP)
- Replies:
**8** - Views:
**1552**

I'm not entirely sure how sudhir3127 got the 14, but that is what I get as well by doing the following procedure: If I'm going to take 30! and divide by a bunch of 3's, I would like to divide by all of the 3 factors in 30! to find the largest value for x. I can figure this out by looking at all of t...

- by VP_RedSoxFan

Thu Jul 31, 2008 9:06 am- Forum: Problem Solving
- Topic: Factorials - anyone know a really quick way
- Replies:
**6** - Views:
**1097**

dubc1982: First of all, good luck on the exam. Please do remember its just an exam. The looser you can be, the clearer you'll think. Secondly, your intuition is correct about there being my PS than DS. That's because there is always the same breakdown, 22 PS and 15 DS. Thirdly, you make a great poin...

- by VP_RedSoxFan

Thu Jul 31, 2008 8:52 am- Forum: GMAT Math
- Topic: I have a week left, where should I focus, DS or PS???
- Replies:
**2** - Views:
**1680**

Here's my unsolicited help on number 2 since I think it is such a classic GMAT problem. Since no one asked for help, feel free to tell me to shut up :). 4^17 - 2^28 = (2^2)^17 - 2^28 = 2^34 - 2^28 from here, factor out a 2^28 leaving you with: 2^28 * (2^6 - 1) Since we know the 2^28 portion just rea...

- by VP_RedSoxFan

Thu Jul 31, 2008 8:45 am- Forum: Problem Solving
- Topic: 2 gmat prep 2 questions
- Replies:
**13** - Views:
**2176**

I agree with Gabriel. Using any of the major test prep providers' books should help and doing more problems help as well. I'd hesitate to go anymore technical into these areas as the GMAT isn't looking for technical knowledge, just your ability to apply specific concepts within a time constraint. Th...

- by VP_RedSoxFan

Thu Jul 31, 2008 8:36 am- Forum: GMAT Math
- Topic: need help on Number Theory and Probability
- Replies:
**2** - Views:
**1874**

I would recommend stopping by Barnes and Noble and picking up a GMAT math book. It'll will have material on these topics. You can buy a math text book, but I suspect they'll go too deep into these subjects. A GMAT book will really just give you what you need to succeed on test day. Plus, you can alw...

- by VP_RedSoxFan

Thu Jul 31, 2008 8:31 am- Forum: GMAT Math
- Topic: Need help with probability and permutation
- Replies:
**1** - Views:
**1545**

I like this problem a lot. Hopefully I can help. If you change the 4^11 into (2^2)^11, then it becomes 2^22. Now, if you look at the left side, you have 21 5's being multiplied by 22 2's. If you match up a 5 and 2, you'll get 21 pairs of 5*2 with one 2 left over. Turn those 21 pairs of a 5 and 2 int...

- by VP_RedSoxFan

Thu Jul 31, 2008 8:26 am- Forum: Problem Solving
- Topic: Help with this problem please
- Replies:
**2** - Views:
**1251**