## Search found 18 matches

#### Can anyone help me figure this one out?

###### Problem Solving

hey debonairdrz,

U have got it right till the equation.
U are doing something wrong while simplyfying it.

3x = sqrt(3)*(x^2)/4
Thus x/4 = 3/sqrt(3)
Thus x = 4*sqrt(3)

Note: I am following the same nomenclature as you are n the solution. as in x is the side of the triangle

by Mr Smith

Wed Apr 25, 2012 12:28 pm
Forum: Problem Solving
Topic: Can anyone help me figure this one out?
Replies: 4
Views: 1168

#### Aristotle DS - Both sufficient but different answers

###### Data Sufficiency

In my experience, all DS questions in which both statements lead to an answer usually lead to the same one. but Strictly speaking, It is nowhere mentioned in the GMAT (at least I have never come across such statement) that both should lead to the same answer for choosing D. My advice: If you come ac...

by Mr Smith

Wed Apr 25, 2012 10:18 am
Forum: Data Sufficiency
Topic: Aristotle DS - Both sufficient but different answers
Replies: 1
Views: 851

#### Manhattan Concept

###### Problem Solving

Ok Bryan88, I'm unfamiliar with the particular method you are referring to. But heres what I can tell you: in your question, the range of mn would lie over the entire number line because both can take negative values. The multiplication that you have done would be valid in two cases: A>3 , B>4 AB>12...

by Mr Smith

Wed Apr 25, 2012 9:48 am
Forum: Problem Solving
Topic: Manhattan Concept
Replies: 2
Views: 830

#### GMAT Prep DS problem

###### Data Sufficiency

NextTarget, So the actual cost can be either greater than (for e.g., if each book was for $1.7 than the estemated cost for each book would be$2 and the net estimated cost would be more than actual cost.)the estimated cost or less than it (The nearest integer cost could less than the actual cost for...

by Mr Smith

Wed Apr 25, 2012 9:12 am
Forum: Data Sufficiency
Topic: GMAT Prep DS problem
Replies: 5
Views: 1153

#### 10 light bulbs

###### Problem Solving

Yes you should always ask such question to gain a better understanding of all concepts. Let the event of the first light bulb failing be E1, for the 2nd be E2 and so on. OK what we need is the Union of the events E1, E2... E10 i.e., P(E1 OR E2 OR E3 OR .... OR E10) From sets we know that n(A union B...

by Mr Smith

Tue Apr 24, 2012 3:27 am
Forum: Problem Solving
Topic: 10 light bulbs
Replies: 3
Views: 1850

#### set theory

###### Problem Solving

Set A is of people who own ambassadors. n(A) = 200 Set F is of people who on fiats n(F) = 400 It is given that n(A Intersection F) = 50 The total number of people is n(A union F) And we know that n(A union F) = n(A) + n(F) - n(A intersection F) =200 + 400-50 = 550 Another way to look at it is when w...

by Mr Smith

Tue Apr 24, 2012 2:49 am
Forum: Problem Solving
Topic: set theory
Replies: 3
Views: 851

#### probability.

###### Problem Solving

Ok heres what I understood from your question: You have 15 letters and 15 corresponding envelops. The 15 letters are placed in the 15 envelops, one in each. You want to find the probability that that each letter is placed in a wrong envelop. If this is the question, it is way beyond the scope of GMA...

by Mr Smith

Tue Apr 24, 2012 2:08 am
Forum: Problem Solving
Topic: probability.
Replies: 6
Views: 1606

#### discount problem

###### Problem Solving

SP = CP * (1+profit/100)
= 250 *(1 + 20/100)
= 250 * 1.2
= 300

Discount= (MP-SP)*100/MP
= 0

by Mr Smith

Mon Apr 23, 2012 8:44 am
Forum: Problem Solving
Topic: discount problem
Replies: 4
Views: 831

#### quick question on divisibility - need expert help

###### Problem Solving

Hey voodoo_child, First Your argument that 12.2 is divisible by 2 is incorrect because: The concept of divisibility is used only for integers as correctly indicated by happyurfriendly. And a number being divisible by definition means would result in no remainder AND an integral quotient. So it is in...

by Mr Smith

Mon Apr 23, 2012 8:32 am
Forum: Problem Solving
Topic: quick question on divisibility - need expert help
Replies: 7
Views: 1022

#### Pentagon sides

###### Problem Solving

Ok heres How I would approach the problem on GMAT Day. given 4 side lengths: 5,4,3,2 Thus maximum length of fifth side: 14 Thus 15 is out Now to find if there is minimum constraint on the 5th side, As GMATguruNY aptly pointed out, Lets find out if the remaining sides can make quadrilateral. Find out...

by Mr Smith

Sun Apr 08, 2012 12:38 am
Forum: Problem Solving
Topic: Pentagon sides
Replies: 11
Views: 3719

#### Tough inference question ...

Hope it helps

by Mr Smith

Sun Apr 08, 2012 12:31 am
Topic: Tough inference question ...
Replies: 3
Views: 1073

#### Tough inference question ...

I think the Answer is B. The writer (of the RC) begins by agreeing that though the author of literary work includes enough substance to indicate the intended meaning, These pointers might not always be enough to narrow down just one intended meaning as in a Map. A map is an exact communication of th...

by Mr Smith

Sat Apr 07, 2012 9:16 am
Topic: Tough inference question ...
Replies: 3
Views: 1073

#### Pentagon sides

###### Problem Solving

You can not follow that method because: 1) You might disregard the important condition of the polygon being complex if you blindly add the limits of the diagonals by apply the triangle rule to the inner triangles. 2) You assume that the minimum of the last side will happen when the diagonals are at ...

by Mr Smith

Sat Apr 07, 2012 8:31 am
Forum: Problem Solving
Topic: Pentagon sides
Replies: 11
Views: 3719

#### Pentagon sides

###### Problem Solving

yep refer to http://www.beatthegmat.com/a-quickier-w ... tml#463160 for a discussion on the lower limit of last side

by Mr Smith

Sat Apr 07, 2012 8:20 am
Forum: Problem Solving
Topic: Pentagon sides
Replies: 11
Views: 3719

#### A quickier way ?

###### Problem Solving

very good ahsgirlie87, there certainly is a lower limit Yes the methods described above are certainly correct and work out very well for finding the upper limit of unknown side. I feel that questions asking or testing the lower limit of the side for a polygon would become too complex and would be be...

by Mr Smith

Sat Apr 07, 2012 8:13 am
Forum: Problem Solving
Topic: A quickier way ?
Replies: 7
Views: 4935