Hi, Request help with understanding of the following question.Thanks.. x + y = ? 1.x^2 + y^2 = 5 2.xy = 2 It should be clear that neither statement is sufficient on its own, but you can pick numbers to verify this: Statement 1: let x=0, so y= +-√5. So, x+y could be √5 or -√5. INSUFFICIENT. St...

In my solution, I made the cut this way: http://gmatmathpro.com/wp-content/uploads/photo-11-2.jpg Which leads to three exposed quarter circles: the one we can see, the one against the knife, and the one against the cutting board. However, you could also make the cut like this: http://gmatmathpro.com...

1) X intercept => 0=mx+c => x=-c/m; Now if the x-intercept =0; it means that m could be either infinity or a non-zero. I believe that "Infinity/Infinity" is undefined. Hence, m will not be equal to Zero. No. This doesn't make sense. What am I missing here? The case of m=0 makes nonsense o...

Five offices have an average of 8 people per office and a median of 7 people per office, and none of the offices are vacant. What is the maximum number of people who can be in the largest office? A. 23 B. 24 C. 25 D. 26 E. 27 although OA is 24, I think 23 will also fit this scenario Pls help... The...

I'd have to say that the original wording leaves some room for ambiguity. I read the line "An insect has one shoe and one sock for each of its twelve legs" as meaning the ratio of socks to feet is 1:1, and the ratio of shoes to feet is 1:1. In other words, we don't have any extra shoes or...

Pete, It's nice to see you after such a long time! This is a problem from GMATClub 700 series document by Bunuel (GC forum moderator). I see why 24!/2^12 works. Essentially, there are 24 pairs of shoe/socks. For each of the legs, there will be 1/2 ways when socks will be put before shoes. Hence, 24...

Just curious, where did you find this problem? Whoever wrote it, besides obviously knowing nothing about insects, clearly ripped it off from this problem that appeared on the 2001 AMC 12. Before looking at those solutions, though, notice that this problem is closely related to another counting probl...

The question is wrong. Please refer D41 question of the OG12 guide.the actual questionis as below. If (x+y)/z > 0, is x <0? (1) x<y (2)z<0 (x+y)/z>0 implies that the quantities (x+y) and z are either both positive or both negative. Statement 1: x<y. This is clearly insufficient, as it tells us noth...