## Search found 24 matches

#### Veritas redemption

##### Re: Veritas redemption

It has been weeks now and there has been no response to my request. If the Veritas offer is no longer valid, please let me know so.

Regards,
psarma

by psarma

Tue Oct 13, 2020 9:13 am
Forum: GMAT Strategy
Topic: Veritas redemption
Replies: 3
Views: 1199

#### If the average (arithmetic mean) of $$x, y$$ and $$15$$ is $$9,$$ and the average of $$x, 2y$$ and $$2$$ is $$7,$$ then

##### Re: If the average (arithmetic mean) of $$x, y$$ and $$15$$ is $$9,$$ and the average of $$x, 2y$$ and $$2$$ is $$7,$$ t

Average of x,y & 15 is 9
i.e (x+y+15)/3 = 9
or x+y=12

Also, average of x,2y & 2 is 7
i.e (x+2y+2)/3 = 7
or x+2y = 19

Subtracting 1st equation from 2nd equation,
we get y = 7

Option C

#### If $$8^c\cdot \sqrt8=\dfrac{8^a}{8^b}$$ then $$a = ?$$

##### Re: If $$8^c\cdot \sqrt8=\dfrac{8^a}{8^b}$$ then $$a = ?$$

$$8^c$$ . $$\sqrt{8}$$ = $$8^{\left(c+\frac{1}{\left(2\right)}\right)}$$
Likewise, $$8^a$$ / $$8^b$$ = $$8^{a-b}$$
Thus, c+1/2=a-b
or a = b+c+1/2

Option E

by psarma

Thu Oct 01, 2020 3:40 pm
Forum: Problem Solving
Topic: If $$8^c\cdot \sqrt8=\dfrac{8^a}{8^b}$$ then $$a = ?$$
Replies: 1
Views: 221

#### Algebra

##### Re: Algebra

Given, 6x = x+9
or 5x=9
i.e x=9/5

so, x/3 = 3/5

by psarma

Thu Oct 01, 2020 3:36 pm
Forum: Problem Solving
Topic: Algebra
Replies: 2
Views: 374

#### Arithmetic

##### Re: Arithmetic

Let the 3 consecutive integers be n, n+1 and n+2
Given, n+(n+1)+(n+2)=k
or 3n+3=k
or 3(n+1)=k
i.e k is thus a multiple of 3.

From the options given, only 201 is a multiple of 3.

by psarma

Thu Oct 01, 2020 3:33 pm
Forum: Problem Solving
Topic: Arithmetic
Replies: 2
Views: 331

#### If $$9^{2x+5}=27^{3x-10},$$ then $$x =$$

##### Re: If $$9^{2x+5}=27^{3x-10},$$ then $$x =$$

$$9^{2x+5}$$ = $$3^{2\left(2x+5\right)}$$
= $$3^{4x+10}$$
Likewise,
$$27^{3x-10}$$ = $$3^{3\left(3x-10\right)}$$
= $$3^{9x-30}$$

Equating the powers together;
4x+10 = 9x-30
i.e 5x=40
or x=8

by psarma

Thu Oct 01, 2020 3:27 pm
Forum: Problem Solving
Topic: If $$9^{2x+5}=27^{3x-10},$$ then $$x =$$
Replies: 3
Views: 334

#### $$x$$ is between

##### Re: $$x$$ is between

Right angled triangle,
so $$x^2$$ + 10 = $$\left(2\sqrt{\left(15\right)}\right)^2$$
Solving for x:
$$x^2$$ =50
or x= $$\sqrt{50}$$
Thus, answer is Option D - between 7 & 8

by psarma

Thu Oct 01, 2020 3:21 pm
Forum: Problem Solving
Topic: $$x$$ is between
Replies: 2
Views: 391

#### If $$5x - 3y = 7$$ and $$2y - 4x = 3,$$ then $$2x - 2y =$$

##### Re: If $$5x - 3y = 7$$ and $$2y - 4x = 3,$$ then $$2x - 2y =$$

5x-3y=7
2y-4x=3
x-y=10
so 2(x-y)=2(10)
i.e 2x-2y=20

by psarma

Thu Oct 01, 2020 3:11 pm
Forum: Problem Solving
Topic: If $$5x - 3y = 7$$ and $$2y - 4x = 3,$$ then $$2x - 2y =$$
Replies: 3
Views: 391

#### Veritas redemption

##### Re: Veritas redemption

Hello,

Can someone pls respond.

by psarma

Wed Sep 30, 2020 10:56 am
Forum: GMAT Strategy
Topic: Veritas redemption
Replies: 3
Views: 1199

#### The integer k, l, and and m are consecutive even integers between 23 and 33. Which of the following...

##### Re: The integer k, l, and and m are consecutive even integers between 23 and 33. Which of the following...

The arithmetic mean of 3 consecutive even integers would be the middle even integer. That rules out both options B and C. For option A to be the answer, the numbers need to be 22,24 & 26, but 22 is outside the range provided. For option E to be the answer, the numbers need to be 30,32 & 34 but 34 is...

#### If a rectangle has perimeter of 20 and a diagonal with length 9, what is the area of the rectangle?

##### Re: If a rectangle has perimeter of 20 and a diagonal with length 9, what is the area of the rectangle?

Let l be the length and b the breadth Perimeter is 20 So, 2(l+b)=20 i.e l+b=10 Squaring both sides, $$^{l^2}$$ + $$^{b^2}$$ + 2lb = 100 Also, diagonal is 9, So, $$^{l^2}$$ + $$^{b^2}$$ = $$^{9^2}$$ Or $$^{l^2}$$ + $$^{b^2}$$ = 81 Subtracting 2nd equation from 1st, we get 2lb = 19 or lb = 9.5 Area = ...

#### If the average (arithmetic mean) of b and c is 5, and the average of c and d is 10, then b - d = A. Cannot be determine

##### Re: If the average (arithmetic mean) of b and c is 5, and the average of c and d is 10, then b - d = A. Cannot be deter

Given $$\frac{b+c}{2}$$ =5
So, b+c = 10

Likewise, $$\frac{c+d}{2}$$ =10
So, c+d=20

Subtracting 2nd equation from 1st,
we get b-d=-10

#### Veritas redemption

##### Veritas redemption

I’ve submitted my details in google docs for the veritas’ prep redemption (7 practice tests).Hope the offer is still valid.

Please let me know if otherwise. Thanks.

Regards,
psarma

by psarma

Fri Sep 25, 2020 10:08 am
Forum: GMAT Strategy
Topic: Veritas redemption
Replies: 3
Views: 1199

#### In triangle $$ABC$$ above, is $$AC$$ greater than $$4?$$

##### Re: In triangle $$ABC$$ above, is $$AC$$ greater than $$4?$$

$$\angle bac$$ + $$\angle abc$$ = $$\angle bcd$$ Thus, $$\angle abc$$ = 2y i.e 2 $$\angle bac$$ Option 1 gives the length of side BC, which is 4 As $$\angle abc$$ = 2 $$\angle bac$$ , hence the side opposite $$\angle abc$$ should be greater than side opposite $$\angle bac$$ . A is thus sufficient. O...

by psarma

Thu Sep 24, 2020 3:45 pm
Forum: Data Sufficiency
Topic: In triangle $$ABC$$ above, is $$AC$$ greater than $$4?$$
Replies: 1
Views: 251

#### June 25, 1982, fell on a Friday. On which day of the week did June 25, 1987, fall? (Note: 1984 was a leap year.)

##### Re: June 25, 1982, fell on a Friday. On which day of the week did June 25, 1987, fall? (Note: 1984 was a leap year.)

June 25, 1982 was a friday 365 days in a regular year, which is 7X52 + 1, so if a given day is friday, then that day + 365 days is the next calendar day June 25, 1983 was thus a Saturday 1984 was a leap year, so one extra day in Feb, making June 25, 1984 a Monday (instead of Sunday) No more leap yea...