## Search found 24 matches

##### Re: Veritas redemption

Hello BTG Admins,

It has been weeks now and there has been no response to my request. If the Veritas offer is no longer valid, please let me know so.

Regards,

psarma

- by psarma

Tue Oct 13, 2020 9:13 am- Forum: GMAT Strategy
- Topic: Veritas redemption
- Replies:
**3** - Views:
**1273**

#### If the average (arithmetic mean) of \(x, y\) and \(15\) is \(9,\) and the average of \(x, 2y\) and \(2\) is \(7,\) then

###### Problem Solving

##### Re: If the average (arithmetic mean) of \(x, y\) and \(15\) is \(9,\) and the average of \(x, 2y\) and \(2\) is \(7,\) t

Average of x,y & 15 is 9

i.e (x+y+15)/3 = 9

or x+y=12

Also, average of x,2y & 2 is 7

i.e (x+2y+2)/3 = 7

or x+2y = 19

Subtracting 1st equation from 2nd equation,

we get y = 7

Option C

- by psarma

Thu Oct 01, 2020 3:44 pm- Forum: Problem Solving
- Topic: If the average (arithmetic mean) of \(x, y\) and \(15\) is \(9,\) and the average of \(x, 2y\) and \(2\) is \(7,\) then
- Replies:
**2** - Views:
**399**

##### Re: If \(8^c\cdot \sqrt8=\dfrac{8^a}{8^b}\) then \(a = ?\)

\(8^c\) . \(\sqrt{8}\) = \(8^{\left(c+\frac{1}{\left(2\right)}\right)}\)

Likewise, \(8^a\) / \(8^b\) = \(8^{a-b}\)

Thus, c+1/2=a-b

or a = b+c+1/2

Option E

- by psarma

Thu Oct 01, 2020 3:40 pm- Forum: Problem Solving
- Topic: If \(8^c\cdot \sqrt8=\dfrac{8^a}{8^b}\) then \(a = ?\)
- Replies:
**1** - Views:
**251**

- by psarma

Thu Oct 01, 2020 3:36 pm- Forum: Problem Solving
- Topic: Algebra
- Replies:
**2** - Views:
**405**

##### Re: Arithmetic

Let the 3 consecutive integers be n, n+1 and n+2

Given, n+(n+1)+(n+2)=k

or 3n+3=k

or 3(n+1)=k

i.e k is thus a multiple of 3.

From the options given, only 201 is a multiple of 3.

Answer C.

- by psarma

Thu Oct 01, 2020 3:33 pm- Forum: Problem Solving
- Topic: Arithmetic
- Replies:
**2** - Views:
**363**

##### Re: If \(9^{2x+5}=27^{3x-10},\) then \(x =\)

\(9^{2x+5}\) = \(3^{2\left(2x+5\right)}\)

= \(3^{4x+10}\)

Likewise,

\(27^{3x-10}\) = \(3^{3\left(3x-10\right)}\)

= \(3^{9x-30}\)

Equating the powers together;

4x+10 = 9x-30

i.e 5x=40

or x=8

Answer C

- by psarma

Thu Oct 01, 2020 3:27 pm- Forum: Problem Solving
- Topic: If \(9^{2x+5}=27^{3x-10},\) then \(x =\)
- Replies:
**3** - Views:
**367**

##### Re: \(x\) is between

Right angled triangle,

so \(x^2\) + 10 = \(\left(2\sqrt{\left(15\right)}\right)^2\)

Solving for x:

\(x^2\) =50

or x= \(\sqrt{50}\)

Thus, answer is Option D - between 7 & 8

- by psarma

Thu Oct 01, 2020 3:21 pm- Forum: Problem Solving
- Topic: \(x\) is between
- Replies:
**2** - Views:
**422**

##### Re: If \(5x - 3y = 7\) and \(2y - 4x = 3,\) then \(2x - 2y =\)

5x-3y=7

2y-4x=3

Add both the equations:

x-y=10

so 2(x-y)=2(10)

i.e 2x-2y=20

Answer E

- by psarma

Thu Oct 01, 2020 3:11 pm- Forum: Problem Solving
- Topic: If \(5x - 3y = 7\) and \(2y - 4x = 3,\) then \(2x - 2y =\)
- Replies:
**3** - Views:
**448**

- by psarma

Wed Sep 30, 2020 10:56 am- Forum: GMAT Strategy
- Topic: Veritas redemption
- Replies:
**3** - Views:
**1273**

#### The integer k, l, and and m are consecutive even integers between 23 and 33. Which of the following...

###### Problem Solving

##### Re: The integer k, l, and and m are consecutive even integers between 23 and 33. Which of the following...

The arithmetic mean of 3 consecutive even integers would be the middle even integer. That rules out both options B and C. For option A to be the answer, the numbers need to be 22,24 & 26, but 22 is outside the range provided. For option E to be the answer, the numbers need to be 30,32 & 34 but 34 is...

- by psarma

Sat Sep 26, 2020 12:01 pm- Forum: Problem Solving
- Topic: The integer k, l, and and m are consecutive even integers between 23 and 33. Which of the following...
- Replies:
**1** - Views:
**225**

#### If a rectangle has perimeter of 20 and a diagonal with length 9, what is the area of the rectangle?

###### Problem Solving

##### Re: If a rectangle has perimeter of 20 and a diagonal with length 9, what is the area of the rectangle?

Let l be the length and b the breadth Perimeter is 20 So, 2(l+b)=20 i.e l+b=10 Squaring both sides, \(^{l^2}\) + \(^{b^2}\) + 2lb = 100 Also, diagonal is 9, So, \(^{l^2}\) + \(^{b^2}\) = \(^{9^2}\) Or \(^{l^2}\) + \(^{b^2}\) = 81 Subtracting 2nd equation from 1st, we get 2lb = 19 or lb = 9.5 Area = ...

- by psarma

Sat Sep 26, 2020 11:53 am- Forum: Problem Solving
- Topic: If a rectangle has perimeter of 20 and a diagonal with length 9, what is the area of the rectangle?
- Replies:
**1** - Views:
**253**

#### If the average (arithmetic mean) of b and c is 5, and the average of c and d is 10, then b - d = A. Cannot be determine

###### Problem Solving

##### Re: If the average (arithmetic mean) of b and c is 5, and the average of c and d is 10, then b - d = A. Cannot be deter

Given \(\frac{b+c}{2}\) =5

So, b+c = 10

Likewise, \(\frac{c+d}{2}\) =10

So, c+d=20

Subtracting 2nd equation from 1st,

we get b-d=-10

Answer is C.

- by psarma

Sat Sep 26, 2020 11:41 am- Forum: Problem Solving
- Topic: If the average (arithmetic mean) of b and c is 5, and the average of c and d is 10, then b - d = A. Cannot be determine
- Replies:
**2** - Views:
**533**

##### Veritas redemption

Hello BTG Admins,

I’ve submitted my details in google docs for the veritas’ prep redemption (7 practice tests).Hope the offer is still valid.

Please let me know if otherwise. Thanks.

Regards,

psarma

- by psarma

Fri Sep 25, 2020 10:08 am- Forum: GMAT Strategy
- Topic: Veritas redemption
- Replies:
**3** - Views:
**1273**

##### Re: In triangle \(ABC\) above, is \(AC\) greater than \(4?\)

\(\angle bac\) + \(\angle abc\) = \(\angle bcd\) Thus, \(\angle abc\) = 2y i.e 2 \(\angle bac\) Option 1 gives the length of side BC, which is 4 As \(\angle abc\) = 2 \(\angle bac\) , hence the side opposite \(\angle abc\) should be greater than side opposite \(\angle bac\) . A is thus sufficient. O...

- by psarma

Thu Sep 24, 2020 3:45 pm- Forum: Data Sufficiency
- Topic: In triangle \(ABC\) above, is \(AC\) greater than \(4?\)
- Replies:
**1** - Views:
**269**

#### June 25, 1982, fell on a Friday. On which day of the week did June 25, 1987, fall? (Note: 1984 was a leap year.)

###### Problem Solving

##### Re: June 25, 1982, fell on a Friday. On which day of the week did June 25, 1987, fall? (Note: 1984 was a leap year.)

June 25, 1982 was a friday 365 days in a regular year, which is 7X52 + 1, so if a given day is friday, then that day + 365 days is the next calendar day June 25, 1983 was thus a Saturday 1984 was a leap year, so one extra day in Feb, making June 25, 1984 a Monday (instead of Sunday) No more leap yea...

- by psarma

Thu Sep 24, 2020 3:33 pm- Forum: Problem Solving
- Topic: June 25, 1982, fell on a Friday. On which day of the week did June 25, 1987, fall? (Note: 1984 was a leap year.)
- Replies:
**2** - Views:
**342**