Search found 24 matches
Re: Veritas redemption
Hello BTG Admins,
It has been weeks now and there has been no response to my request. If the Veritas offer is no longer valid, please let me know so.
Regards,
psarma
- by psarma
Tue Oct 13, 2020 9:13 am- Forum: GMAT Strategy
- Topic: Veritas redemption
- Replies: 3
- Views: 1680
If the average (arithmetic mean) of \(x, y\) and \(15\) is \(9,\) and the average of \(x, 2y\) and \(2\) is \(7,\) then
Problem Solving
Re: If the average (arithmetic mean) of \(x, y\) and \(15\) is \(9,\) and the average of \(x, 2y\) and \(2\) is \(7,\) t
Average of x,y & 15 is 9
i.e (x+y+15)/3 = 9
or x+y=12
Also, average of x,2y & 2 is 7
i.e (x+2y+2)/3 = 7
or x+2y = 19
Subtracting 1st equation from 2nd equation,
we get y = 7
Option C
- by psarma
Thu Oct 01, 2020 3:44 pm- Forum: Problem Solving
- Topic: If the average (arithmetic mean) of \(x, y\) and \(15\) is \(9,\) and the average of \(x, 2y\) and \(2\) is \(7,\) then
- Replies: 2
- Views: 496
Re: If \(8^c\cdot \sqrt8=\dfrac{8^a}{8^b}\) then \(a = ?\)
\(8^c\) . \(\sqrt{8}\) = \(8^{\left(c+\frac{1}{\left(2\right)}\right)}\)
Likewise, \(8^a\) / \(8^b\) = \(8^{a-b}\)
Thus, c+1/2=a-b
or a = b+c+1/2
Option E
- by psarma
Thu Oct 01, 2020 3:40 pm- Forum: Problem Solving
- Topic: If \(8^c\cdot \sqrt8=\dfrac{8^a}{8^b}\) then \(a = ?\)
- Replies: 1
- Views: 310
- by psarma
Thu Oct 01, 2020 3:36 pm- Forum: Problem Solving
- Topic: Algebra
- Replies: 2
- Views: 495
Re: Arithmetic
Let the 3 consecutive integers be n, n+1 and n+2
Given, n+(n+1)+(n+2)=k
or 3n+3=k
or 3(n+1)=k
i.e k is thus a multiple of 3.
From the options given, only 201 is a multiple of 3.
Answer C.
- by psarma
Thu Oct 01, 2020 3:33 pm- Forum: Problem Solving
- Topic: Arithmetic
- Replies: 2
- Views: 467
Re: If \(9^{2x+5}=27^{3x-10},\) then \(x =\)
\(9^{2x+5}\) = \(3^{2\left(2x+5\right)}\)
= \(3^{4x+10}\)
Likewise,
\(27^{3x-10}\) = \(3^{3\left(3x-10\right)}\)
= \(3^{9x-30}\)
Equating the powers together;
4x+10 = 9x-30
i.e 5x=40
or x=8
Answer C
- by psarma
Thu Oct 01, 2020 3:27 pm- Forum: Problem Solving
- Topic: If \(9^{2x+5}=27^{3x-10},\) then \(x =\)
- Replies: 3
- Views: 482
Re: \(x\) is between
Right angled triangle,
so \(x^2\) + 10 = \(\left(2\sqrt{\left(15\right)}\right)^2\)
Solving for x:
\(x^2\) =50
or x= \(\sqrt{50}\)
Thus, answer is Option D - between 7 & 8
- by psarma
Thu Oct 01, 2020 3:21 pm- Forum: Problem Solving
- Topic: \(x\) is between
- Replies: 2
- Views: 502
Re: If \(5x - 3y = 7\) and \(2y - 4x = 3,\) then \(2x - 2y =\)
5x-3y=7
2y-4x=3
Add both the equations:
x-y=10
so 2(x-y)=2(10)
i.e 2x-2y=20
Answer E
- by psarma
Thu Oct 01, 2020 3:11 pm- Forum: Problem Solving
- Topic: If \(5x - 3y = 7\) and \(2y - 4x = 3,\) then \(2x - 2y =\)
- Replies: 3
- Views: 678
- by psarma
Wed Sep 30, 2020 10:56 am- Forum: GMAT Strategy
- Topic: Veritas redemption
- Replies: 3
- Views: 1680
The integer k, l, and and m are consecutive even integers between 23 and 33. Which of the following...
Problem Solving
Re: The integer k, l, and and m are consecutive even integers between 23 and 33. Which of the following...
The arithmetic mean of 3 consecutive even integers would be the middle even integer. That rules out both options B and C. For option A to be the answer, the numbers need to be 22,24 & 26, but 22 is outside the range provided. For option E to be the answer, the numbers need to be 30,32 & 34 b...
- by psarma
Sat Sep 26, 2020 12:01 pm- Forum: Problem Solving
- Topic: The integer k, l, and and m are consecutive even integers between 23 and 33. Which of the following...
- Replies: 1
- Views: 321
If a rectangle has perimeter of 20 and a diagonal with length 9, what is the area of the rectangle?
Problem Solving
Re: If a rectangle has perimeter of 20 and a diagonal with length 9, what is the area of the rectangle?
Let l be the length and b the breadth Perimeter is 20 So, 2(l+b)=20 i.e l+b=10 Squaring both sides, \(^{l^2}\) + \(^{b^2}\) + 2lb = 100 Also, diagonal is 9, So, \(^{l^2}\) + \(^{b^2}\) = \(^{9^2}\) Or \(^{l^2}\) + \(^{b^2}\) = 81 Subtracting 2nd equation from 1st, we get 2lb = 19 or lb = 9.5 Area = ...
- by psarma
Sat Sep 26, 2020 11:53 am- Forum: Problem Solving
- Topic: If a rectangle has perimeter of 20 and a diagonal with length 9, what is the area of the rectangle?
- Replies: 1
- Views: 313
If the average (arithmetic mean) of b and c is 5, and the average of c and d is 10, then b - d = A. Cannot be determine
Problem Solving
Re: If the average (arithmetic mean) of b and c is 5, and the average of c and d is 10, then b - d = A. Cannot be deter
Given \(\frac{b+c}{2}\) =5
So, b+c = 10
Likewise, \(\frac{c+d}{2}\) =10
So, c+d=20
Subtracting 2nd equation from 1st,
we get b-d=-10
Answer is C.
- by psarma
Sat Sep 26, 2020 11:41 am- Forum: Problem Solving
- Topic: If the average (arithmetic mean) of b and c is 5, and the average of c and d is 10, then b - d = A. Cannot be determine
- Replies: 2
- Views: 1135
Veritas redemption
Hello BTG Admins,
I’ve submitted my details in google docs for the veritas’ prep redemption (7 practice tests).Hope the offer is still valid.
Please let me know if otherwise. Thanks.
Regards,
psarma
- by psarma
Fri Sep 25, 2020 10:08 am- Forum: GMAT Strategy
- Topic: Veritas redemption
- Replies: 3
- Views: 1680
Re: In triangle \(ABC\) above, is \(AC\) greater than \(4?\)
\(\angle bac\) + \(\angle abc\) = \(\angle bcd\) Thus, \(\angle abc\) = 2y i.e 2 \(\angle bac\) Option 1 gives the length of side BC, which is 4 As \(\angle abc\) = 2 \(\angle bac\) , hence the side opposite \(\angle abc\) should be greater than side opposite \(\angle bac\) . A is thus sufficient. O...
- by psarma
Thu Sep 24, 2020 3:45 pm- Forum: Data Sufficiency
- Topic: In triangle \(ABC\) above, is \(AC\) greater than \(4?\)
- Replies: 1
- Views: 336
June 25, 1982, fell on a Friday. On which day of the week did June 25, 1987, fall? (Note: 1984 was a leap year.)
Problem Solving
Re: June 25, 1982, fell on a Friday. On which day of the week did June 25, 1987, fall? (Note: 1984 was a leap year.)
June 25, 1982 was a friday 365 days in a regular year, which is 7X52 + 1, so if a given day is friday, then that day + 365 days is the next calendar day June 25, 1983 was thus a Saturday 1984 was a leap year, so one extra day in Feb, making June 25, 1984 a Monday (instead of Sunday) No more leap yea...
- by psarma
Thu Sep 24, 2020 3:33 pm- Forum: Problem Solving
- Topic: June 25, 1982, fell on a Friday. On which day of the week did June 25, 1987, fall? (Note: 1984 was a leap year.)
- Replies: 2
- Views: 456