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there are 4 even nos. between 1 and 8, these are 2,4,6,8 out of these even nos any two can be selected in 4c2 ways=6, now, sum will be eight if the selected numbers are 2 and 6, so for first draw we can have two options either it will be 2 or 6 and for the second draw we have only one option left i...

by manpsingh87

Wed Jun 22, 2011 7:56 pm
Forum: Problem Solving
Topic: Probability
Replies: 6
Views: 1160

From the even numbers between 1 and 9, two different even numbers are to be choosen at random. what is the probability that their sum will be 8? a)1/6 b)3/16 c)1/4 d)1/3 e)1/2 we have 2 events: 2+6, 6+2 my question is how to know quickly the number of summing events which =12? there are 4 even nos....

by manpsingh87

Wed Jun 22, 2011 10:23 am
Forum: Problem Solving
Topic: Probability
Replies: 6
Views: 1160

A function f(x) defined on the set of whole numbers is such that f(x + y) = f(x) × f(y). If it is given that f(1) = (1 ÷ 3), find the sum of the following infinite series: f(0) + f(1) + f(2) + f(3) + .... 1) (1 ÷ 2) 2) (3 ÷ 2) 3) (2 ÷ 3) 4) The given infinite series is not convergent and, henc...

by manpsingh87

Tue Jun 21, 2011 7:46 am
Forum: Problem Solving
Topic: Function
Replies: 5
Views: 1074

Out of seven models, all of different heights, five models will be chosen to pose for a photograph. If the five models are to stand in a line from shortest to tallest, and the fourth-tallest and sixth-tallest models cannot be adjacent, how many different arrangements of five models are possible? 6 ...

by manpsingh87

Mon Jun 20, 2011 10:18 am
Forum: Problem Solving
Topic: p and c
Replies: 2
Views: 908

someone explain this. BD=sqrt(12^2+20^2); BD=25; let EC=x; and ED=y; therefore, area of triangle BDC= Area of triangle BEC+ area of traingle CED; 1/2*15*20= 1/2*x*y+1/2*x*(25-y); 300=xy+x(25-y); 300=xy+25x-xy; x=12; also in triangle BEC we have; x^2+y^2=15^2; y^2=225-144; y^2=81; y=9; thusBE=25-9=1...

by manpsingh87

Sun Jun 19, 2011 8:39 pm
Forum: Problem Solving
Topic: kaplan problem
Replies: 2
Views: 828

If 1/2 of the money in a certain trust fund was invested in stocks, 1/4 in bonds, 1/5 in a mutual fund, and the remaining $10.000 in a government certificate, what was the total amount of the trust fund? A.$100.000 B.$150.000 C.$200.000 D.$500.000 E.$2.000.000 let the initial amount be x; 1/2=50%; ...

by manpsingh87

Sat Jun 18, 2011 11:40 pm
Forum: Problem Solving
Topic: If 1/2 of the money in a certain trust fund was invested...
Replies: 4
Views: 4057

A teacher prepares a test. She gives 5 objective types questions out of which 4 are to be answered. Find the total ways in which they can be answered if the first 2 questions have 3 choices and the last 3 have 4 choices. A. 255 B. 816 C. 192 D. 100 E. 144 Ans - 816 How to solve this. Thanks in Adva...

by manpsingh87

Mon Jun 13, 2011 8:27 pm
Forum: Problem Solving
Topic: Probability
Replies: 2
Views: 2614

Can any of the experts please help in this question?? Bill has a small deck of 12 playing cards made up of only 2 suits of 6 cards each. Each of the 6 cards within a suit has a different value from 1 to 6; thus, for each value from 1 to 6, there are two cards in the deck with that value. Bill likes...

by manpsingh87

Sun Jun 12, 2011 11:54 pm
Forum: Problem Solving
Topic: Probability question :( [700+]
Replies: 12
Views: 1744

2^(2x+8)+1=32*2^x A. 4 B. 2 C. 0 D. -2 E -4 [spoiler]OA : E[/spoiler] Best is to substitute each AO and find it, but if the choices are not given, how? 2^(2x+8)+1=32*2^x ; 2^2x*256+1=32*2^x; let 2^x=y;-----------1) 256y^2-32y+1=0; (16y-1)=0; y=1/16; from 1) we have; 2^x=1/16; 2^x=2^-4; hence x=-4, ...

by manpsingh87

Sun Jun 12, 2011 8:09 am
Forum: Problem Solving
Topic: Solve for x
Replies: 3
Views: 1024

if an integer is divisible by both 9 & 12, then it must be divisible by all of the following except A. 36 B. 27 C. 18 D. 12 E. 9 [spoiler]OA : B[/spoiler] My answer is B since 27 is not a factor of the number which can be divisible by 9 & 12. All others are multiple of 9 & 12 except 27. Any other d...

by manpsingh87

Sun Jun 12, 2011 7:39 am
Forum: Problem Solving
Topic: Integer n
Replies: 4
Views: 774

Problem - Find the greatest number, which will divide 215,167 and 135 so as to leave the same remainder in each case. I understood that we have to take the GCD of each number. But 167 is a prime. How do we solve this? let k be the number which will leave same remainder 'r' in each case when divided...

by manpsingh87

Sun Jun 12, 2011 1:06 am
Forum: Problem Solving
Topic: Number properties
Replies: 5
Views: 1955

a rainstorm increased the amount of water from 124 bn gallons to 138 bn gallons. If storm increased the amount of water to 82% of the total capacity, approx how many bn gallons of water was the reservoir short of the total capacity prior to the storm. a 9 b 14 c 25 d 30 e 44 let the capacity of res...

by manpsingh87

Sat Jun 11, 2011 4:43 am
Forum: Problem Solving
Topic: PS
Replies: 4
Views: 791

if -2x > 3y ,is x negative? 1. y>0 2. 2x+5y-20=0 1) y>0; multiplying 3 on both sides we have; 3y>0; for -2x to become greater than 3y; x must be negative; because positive quantity is always greater than negative quantity, hence x must be negative, hence 1 alone is sufficient to answer the question...

by manpsingh87

Fri Jun 10, 2011 10:50 am
Forum: Data Sufficiency
Topic: numbers : from GMAT prep
Replies: 4
Views: 964

The positive integers m and n leave remainders of 2 and 3,respectively,when divided by 6. m > n. What is the remainder when m-n is divisible by 6 ? A-1 B-2 C-3 D-4 E-5 PLEASE SOLVE HOW THANKS m=6k+2; n=6t+3; k,t (1,2,3 are +ve integers..) since m>n; one way is to solve it by substituting values, pu...

by manpsingh87

Fri Jun 10, 2011 10:42 am
Forum: Problem Solving
Topic: PROBLEM SOLVING
Replies: 4
Views: 942

Circular gears P and Q start rotating at constant speeds. Gear P makes 10 rev/min and Q makes 40 rev/min. How many seconds after the gears start rotating will Q have made exactly 6 revolutions more than P. a. 6 b. 8 c. 10 d. 12 e. 15 D p=10 rev/min= 10/60 rev/sec. p=1/6 rev/sec. q=40 rev/min=40/60 ...

by manpsingh87

Fri Jun 10, 2011 10:33 am
Forum: Problem Solving
Topic: gears
Replies: 8
Views: 1219