Seamus has 3 times as many marbles as Ronit, and Taj has 7 times as many marbles as Ronit. If Seamus has \(s\) marbles, then, in terms of \(s,\) how many marbles do Seamus, Ronit, and Taj have together?
(A) \(\dfrac{3s}7\)
(B) \(\dfrac{7s}3\)
(C) \(\dfrac{11s}3\)
(D) \(7s\)
(E) \(11s\)
[spoiler]OA=C[/spoiler]
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Seamus has 3 times as many marbles as Ronit, and Taj has 7 times as many marbles as Ronit. If Seamus has \(s\) marbles,
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Gmat_mission
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JamesHammel
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First we can determine the amount in the amount Ronit (R) has :
S = 3R
Taj (T) = 7 R
S + T + R = 3R + 7R +R = 11R
Thus, 11R = 11 * S/3 (C)
S = 3R
Taj (T) = 7 R
S + T + R = 3R + 7R +R = 11R
Thus, 11R = 11 * S/3 (C)
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Scott@TargetTestPrep
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Solution:Gmat_mission wrote: ↑Sun May 31, 2020 12:58 pmSeamus has 3 times as many marbles as Ronit, and Taj has 7 times as many marbles as Ronit. If Seamus has \(s\) marbles, then, in terms of \(s,\) how many marbles do Seamus, Ronit, and Taj have together?
(A) \(\dfrac{3s}7\)
(B) \(\dfrac{7s}3\)
(C) \(\dfrac{11s}3\)
(D) \(7s\)
(E) \(11s\)
[spoiler]OA=C[/spoiler]
Since Seamus has s marbles and he has 3 times as many marbles as Ronit, Ronit has s/3 marbles. Since Tai has 7 times as many marbles as Ronit, Tai has 7s/3 marbles. Thus, the 3 individuals together have a total of s + s/3 + 7s/3 = 3s/3 + s/3 + 7s/3 = 11s/3 marbles.
Answer: C
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