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DanaJ
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Are you sure that the ratios are correct? I'm not getting the OA... Or maybe I'm just wrong...
First, you have that j/(f+m) = 1/3, with f+m = 3j. So j+f+m = 1200 is the equivalent of j+3j = 4j = 1200, with j = 300. Suppose that f is the biggest it can be, meaning 1200 - 300 = 900 (with m = 0). This still is not consistent with f/(j+m) = 7/2, since 800/300 = 8/3 < 7/2....
[Sorry, I corrected it]
First, you have that j/(f+m) = 1/3, with f+m = 3j. So j+f+m = 1200 is the equivalent of j+3j = 4j = 1200, with j = 300. Suppose that f is the biggest it can be, meaning 1200 - 300 = 900 (with m = 0). This still is not consistent with f/(j+m) = 7/2, since 800/300 = 8/3 < 7/2....
[Sorry, I corrected it]
Last edited by DanaJ on Sat Jan 24, 2009 8:23 am, edited 1 time in total.
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piyush_nitt
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Yep , something wrong . I am not getting answer as well. Did same thing what you did Danaj.DanaJ wrote:Are you sure that the ratios are correct? I'm not getting the OA... Or maybe I'm just wrong...
First, you have that j/(f+m) = 1/3, with f+m = 3j. So j+f+m = 1200 is the equivalent of j+3j = 4j = 1200, with j = 400. Suppose that f is the biggest it can be, meaning 1200 - 400 = 800 (with m = 0). This still is not consistent with f/(j+m) = 7/2, since 800/400 = 2 < 7/2....
