Hello,
Can you please assist with this:
Some computers at a certain company are Brand X and the rest are Brand Y. If the ratio of the number of Brand Y computers to the number of Brand X computers at the company is 5 to 6, how many of the computers are Brand Y?
(1) There are 80 more brand X computers than Brand Y computers at the company
(2) There is a total of 880 computers at the company
OA: D
I was not clear with the approach explained in the OG.
Thanks for your help.
Best Regards,
Sri
Ratio problem?
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Lets Brand X computers be 6x
Lets Brand Y computers be 5x
Total compueters = 11x
St1: 6x  5x = 80 or x = 80
# of Brand Y computers = 80 * 5 = 400
Sufficient
St2: 11x = 880 or x = 80
# of Brand Y computers = 80 * 5 = 400
Sufficient
Hence D
Lets Brand Y computers be 5x
Total compueters = 11x
St1: 6x  5x = 80 or x = 80
# of Brand Y computers = 80 * 5 = 400
Sufficient
St2: 11x = 880 or x = 80
# of Brand Y computers = 80 * 5 = 400
Sufficient
Hence D
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Question stem:gmattesttaker2 wrote:Hello,
Can you please assist with this:
Some computers at a certain company are Brand X and the rest are Brand Y. If the ratio of the number of Brand Y computers to the number of Brand X computers at the company is 5 to 6, how many of the computers are Brand Y?
(1) There are 80 more brand X computers than Brand Y computers at the company
(2) There are a total of 880 computers at the company
OA: D
y/x = 5/6
5x = 6y.
Statement 1: There are 80 more brand X computers than Brand Y computers at the company.
x = y + 80.
Since we have two variables and two distinct linear equations (5x=6y and x=y+80), we can solve for each variable.
SUFFICIENT.
Statement 2: There are a total of 880 computers at the company.
x+y = 880.
Since we have two variables and two distinct linear equations (5x=6y and x+y=880), we can solve for each variable.
SUFFICIENT.
The correct answer is D.
A quick way to solve for x and y that requires little algebra:
y/x = 5/6.
If x=6 and y=5, then xy = 1.
Statement 1 indicates that xy = 80.
To yield a difference 80 TIMES AS GREAT as xy=1, x and y must each be multiplied by a FACTOR OF 80:
x = 6*80 = 480.
y = 5*80 = 400.
These values satisfy both statements:
xy = 80.
x+y = 880.
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Solution:gmattesttaker2 wrote: ↑Tue May 28, 2013 10:13 pm
Some computers at a certain company are Brand X and the rest are Brand Y. If the ratio of the number of Brand Y computers to the number of Brand X computers at the company is 5 to 6, how many of the computers are Brand Y?
(1) There are 80 more brand X computers than Brand Y computers at the company
(2) There is a total of 880 computers at the company
OA: D
Question Stem Analysis:
We need to determine the number of Brand Y computers at a certain company, given that the ratio of the number of brand Y computers to the number of Brand X computers at the company is 5 to 6. That is, if let the number of Brand Y computers be y, then the number of Brand X computers is 6y / 5 (notice that y / (6y/5) = 5/6). We need to determine the value of y.
Statement One Alone:
We can create the equation:
y + 80 = 6y/5
80 = y/5
400 = y
Statement one alone is sufficient.
Statement Two Alone:
We can create the equation:
y + 6y/5 = 880
11y/5 = 880
y/5 = 80
y = 400
Statement two alone is sufficient
Answer: D
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