Problem Solving

Rank those three in order from smallest to biggest.

I. 47/150
II. 111/350
III.299/900


(A) I, II, III
(B) I, III, II
(C) II, I, III
(D) II, III, I
(E) III, I, II


OA A

Source: Magoosh

BTGmoderatorDC wrote: ↑

Thu Jan 06, 2022 9:27 pm

Rank those three in order from smallest to biggest.

I. 47/150
II. 111/350
III.299/900


(A) I, II, III
(B) I, III, II
(C) II, I, III
(D) II, III, I
(E) III, I, II


OA A

Source: Magoosh

Let's analyze one by one,

I. \(\dfrac{47}{150} = \dfrac{48}{150} - \dfrac{1}{150} = 0.32 - \dfrac{1}{150}\)

II. \(\dfrac{111}{350} = \dfrac{112}{350} - \dfrac{1}{350}= 0.32 - \dfrac{1}{350}\)

III. \(\dfrac{299}{900} = \dfrac{300}{900} - \dfrac{1}{900}= 0.33333 - \dfrac{1}{900}\)

So we can say that

\(I < II < III\)

Therefore, A