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Question of the Day - 25th August, 2009

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Question of the Day - 25th August, 2009

by quant-master » Mon Aug 24, 2009 3:29 pm
Question 2:

X,Y > 0 ,If X^3 = Y, is Y a fraction?

(1) X^2 is a fraction
(2) X >Y

OAs will be posted in 24 hrs time

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by keough » Mon Aug 24, 2009 3:40 pm
x^2 is a fraction
therefore x is a fraction
therefore x^3 is a fraction
therefore y is a fraction
St1 is sufficient

St2 says nothing about x, not sufficient
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by pradeepsarathy » Mon Aug 24, 2009 6:50 pm
IMO A -

From the question stem, we can figure out that if 'y' has to be a fraction,then 'x' has to be a fraction too..

Stmt 1 - x^2 is a fraction.

This implies 'x' has to be a fraction.
Hence 'y' will also be a fraction
Sufficient

Stmt 2 - X>Y

Insufficient.
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INHO

by kc_raj » Mon Aug 24, 2009 7:49 pm
IMHO D,

x2is fraction so x is a fraction >0, so x3 is fraction too, A suff

x>x3>0 only way it is possible is if 0<x<1, so x is a fraction, x3 is a fraction, B suff

D is ans
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by mehravikas » Tue Aug 25, 2009 1:26 am
IMO - D

statement 2 - we can conclude that x != y because x > y

therefore x and not equal to 1. Now there is only one possibility 0 < x < 1.
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by quant-master » Tue Aug 25, 2009 3:49 pm
OA is D. Let me know if anybody needs further explanation

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