## Que: With the increase of 20% in the price of milk, a housewife can buy 5 liters less quantity for $60........... ##### This topic has expert replies Elite Legendary Member Posts: 3846 Joined: 24 Jul 2015 Location: Las Vegas, USA Thanked: 19 times Followed by:36 members ### Que: With the increase of 20% in the price of milk, a housewife can buy 5 liters less quantity for$60...........

by [email protected] Revolution » Thu Jan 28, 2021 11:56 pm

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A

B

C

D

E

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Que: With the increase of 20% in the price of milk, a housewife can buy 5 liters less quantity for $60 than she was buying before the increase. What was the initial price per liter of milk? (A)$2.00
(B) $2.50 (C)$2.75
(D) $3.00 (E)$3.50

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### Re: Que: With the increase of 20% in the price of milk, a housewife can buy 5 liters less quantity for $60........... by [email protected] Revolution » Wed Feb 03, 2021 10:29 pm Solution: The price of milk is increased by 20%. Let the original price of milk per liter be$10.

Increased price: $$\frac{120}{100}$$ * $10 =$12[/m]

Number of liters of milk: $$\frac{Total\ price\ }{price\ per\ litre}$$

Number of liters of milk before increase: $$\frac{60}{10}$$=6

Number of liters of milk after increase: $$\frac{60}{12}$$=5

The difference in the quantity of milk obtained: 6 - 5 = 1

Thus, for the $10 initial price, the difference is 1 liter. For 5 liters difference, $$\frac{10}{5}$$ =$2

Therefore, A is the correct answer.

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### Re: Que: With the increase of 20% in the price of milk, a housewife can buy 5 liters less quantity for $60........... by [email protected] » Fri Apr 16, 2021 8:22 am [email protected] Revolution wrote: Thu Jan 28, 2021 11:56 pm Que: With the increase of 20% in the price of milk, a housewife can buy 5 liters less quantity for$60 than she was buying before the increase. What was the initial price per liter of milk?

(A) $2.00 (B)$2.50
(C) $2.75 (D)$3.00
(E) \$3.50
Solution:

We can let p be the initial price per liter of the milk and create the equation:

60/(1.2p) = 60/p - 5

50/p = 60/p - 5

50 = 60 - 5p

5p = 10

p = 2