## Que: When P is divided by 2, is the remainder 1?

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### Que: When P is divided by 2, is the remainder 1?

by [email protected] Revolution » Fri Aug 13, 2021 6:10 pm

00:00

A

B

C

D

E

## Global Stats

Que: When P is divided by 2, is the remainder 1?

(1) $$\left(-1\right)^{\left(P+2\right)}=1$$
(2) P is a prime.

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### Re: Que: When P is divided by 2, is the remainder 1?

by [email protected] Revolution » Sun Aug 15, 2021 8:58 pm

00:00

A

B

C

D

E

## Global Stats

Solution: Solution: To save time and improve accuracy on DS questions in GMAT, learn and apply the Variable Approach.

Forget conventional ways of solving math questions. For DS problems, the VA (Variable Approach) method is the quickest and easiest way to find the answer without actually solving the problem. Remember that equal numbers of variables and independent equations ensure a solution.

Visit https://www.mathrevolution.com/gmat/lesson for details.

Now we will solve this DS question using the Variable Approach.

Let’s apply the 3 steps suggested previously.

Follow the first step of the Variable Approach by modifying and rechecking the original condition and the question.

We have to find ‘Is remainder 1 when P is divided by 2.

Follow the second and the third step: From the original condition, we have 1 variable (P). To match the number of variables with the number of equations, we need 1 equation. Since conditions (1) and (2) will provide 1 equation each, D would most likely be the answer.

Recall 3- Principles and Choose D as the most likely answer.

Let’s look at both conditions combined together.

Condition (1) tells us that $$\left(-1\right)^{P+2}$$= 1.

=> $$\left(-1\right)^{even}$$ gives us 1.

Hence, P + 2 = even. Therefore, P = even – 2 = even – even = even.

If P is even, then the remainder, when P divided by 2, is 0. It is not 1.

The answer is unique NO; condition (1) alone is sufficient according to Common Mistake Type 1 which states that the answer should be a unique YES or a NO.

Condition (2) tells us that P is a prime.

=> If P = 2 remainder is 0 – is remainder 1 - NO

=> If P = any other prime number which is all odd then the remainder is 1 –YES

The answer is not a unique YES or a NO; both conditions combined are not sufficient according to Common Mistake Type 1 which states that the answer should be a unique YES or a NO.

Condition (1) alone is not sufficient.

Therefore, A is the correct answer.