Que: With the increase of 20% in the price of milk, a housewife can buy 5 liters less quantity for $60 than she was buying before the increase. What was the initial price per liter of milk?
(A) $2.00
(B) $2.50
(C) $2.75
(D) $3.00
(E) $3.50
Que: With the increase of 20% in the price of milk, a housewife can buy 5 liters less quantity for $60...........
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- Max@Math Revolution
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Solution: The price of milk is increased by 20%.
Let the original price of milk per liter be $10.
Increased price: \(\frac{120}{100}\) * $10 = $12[/m]
Number of liters of milk: \(\frac{Total\ price\ }{price\ per\ litre}\)
Number of liters of milk before increase: \(\frac{60}{10}\)=6
Number of liters of milk after increase: \(\frac{60}{12}\)=5
The difference in the quantity of milk obtained: 6 - 5 = 1
Thus, for the $10 initial price, the difference is 1 liter.
For 5 liters difference, \(\frac{10}{5}\) = $2
Therefore, A is the correct answer.
Answer A
Let the original price of milk per liter be $10.
Increased price: \(\frac{120}{100}\) * $10 = $12[/m]
Number of liters of milk: \(\frac{Total\ price\ }{price\ per\ litre}\)
Number of liters of milk before increase: \(\frac{60}{10}\)=6
Number of liters of milk after increase: \(\frac{60}{12}\)=5
The difference in the quantity of milk obtained: 6 - 5 = 1
Thus, for the $10 initial price, the difference is 1 liter.
For 5 liters difference, \(\frac{10}{5}\) = $2
Therefore, A is the correct answer.
Answer A
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Solution:Max@Math Revolution wrote: ↑Thu Jan 28, 2021 11:56 pmQue: With the increase of 20% in the price of milk, a housewife can buy 5 liters less quantity for $60 than she was buying before the increase. What was the initial price per liter of milk?
(A) $2.00
(B) $2.50
(C) $2.75
(D) $3.00
(E) $3.50
We can let p be the initial price per liter of the milk and create the equation:
60/(1.2p) = 60/p - 5
50/p = 60/p - 5
50 = 60 - 5p
5p = 10
p = 2
Answer: A
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