Product of the lengths of AD and BC

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by Shawshank » Wed Mar 10, 2010 2:37 am
It is mentioned in the diagram that both the angles are perpendicular..

IMO -- A

No where is it mentioned that D is the midpoint.
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by blaster » Thu Mar 11, 2010 2:58 am
so,what is the correct OA?

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by salmaan » Sun Mar 14, 2010 6:03 pm
Why does it matter what the midpoint is? BH/2 = area. That's all you need to know.

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by fluke » Sun Jan 30, 2011 5:32 am
OA: A

Q: What is AD*BC


I.
(1/2)*AC*BE=(1/2)*BC*AD [Area of triangle will be the same]
AC*BE=BC*AD
AC*BE=60
Therefore, BC*AD=60. Found the answer to the question. Sufficient.

II. BC=8. Don't know whether BC=AC or DE=BE. This triangle can be formed in many ways each having different BE, AD, AC and BC. Not sufficient.

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by GMATGuruNY » Sun Jan 30, 2011 1:56 pm
Nijeesh wrote:Image

In the figure above, what is the product of the lengths of AD and BC?
(1) The product of the lengths of AC and BE is 60.
(2) The length of BC is 8.
No math is needed here.

Any side of a triangle can be considered the base, and each base has a corresponding height.
To draw the height that corresponds to a given base, start at the vertex opposite the base and draw a line that forms a right angle with the base.

In the triangle above:
BE is the height that corresponds to base AC.
AD is the height that corresponds to base BC.

We know that A = 1/2*b*h. No matter which base and corresponding height are used, the area must remain the same. Thus, AC*BE = BC*AD.

Statement 1: AC*BE = 60
Thus, BC*AD = 60.
Sufficient.

Statement 2: BC = 8
No way to determine AD.
Insufficient.

The correct answer is A.
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