For which of the following function is f(a+b) = f(a) = f(b) for all positive numbers a and b?
a) f(x) = x^2 (x square)
b) f(x) =x+1
c) f(x) = root x
d) f(x) = 2/x
e) f(x) = -3x
i really dont have any idea how to solve this...please help...
pleas help....function question
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Let a = 2, b = 5, a+b = 7
1. f(x) = x^2 so f(a) = 4, f(b) = 25 and a + b = 29
but, f(a+b) = 49, No
2. f(x) = x + 1 so f(a) = 3, f(b) = 7 and a + b = 10
but, f(a+b) = 9, No
3. N0
4. N0
5. f(x) = -3x so f(a) = -6, f(b) = -15 and a + b = -21
Similarly f(a+b) = f(7) = -21
ans E.
1. f(x) = x^2 so f(a) = 4, f(b) = 25 and a + b = 29
but, f(a+b) = 49, No
2. f(x) = x + 1 so f(a) = 3, f(b) = 7 and a + b = 10
but, f(a+b) = 9, No
3. N0
4. N0
5. f(x) = -3x so f(a) = -6, f(b) = -15 and a + b = -21
Similarly f(a+b) = f(7) = -21
ans E.
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Is E the right answer..question is asking f(a+b)=f(a)=(b)
evaluating for E as per Suyog, f(a+b)=-21;f(a)=-6;f(b)=-15..so, how does f(a+b)=f(a)=f(b)..
Please explain..
evaluating for E as per Suyog, f(a+b)=-21;f(a)=-6;f(b)=-15..so, how does f(a+b)=f(a)=f(b)..
Please explain..
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moreonalps, u r correct but in the Qs itself it is saying that f(a + b) = f(a) = f(b). It should be f(a + b) = f(a) + f(b). Oooppppppsssss! Ok! This is solely my understanding and I personally assume this from the solution offered by Suyog. Suyog, am I wrong?
Correct me If I am wrong
Regards,
Amitava
Regards,
Amitava
you are right Camitava..
I had solved something like this earlier while practicing....
and it was f(a+b) = f(a) + f(b)
So i solved considering that.. LOL
bushra, can u pls confirm the question...
Thanks guys!
I had solved something like this earlier while practicing....
and it was f(a+b) = f(a) + f(b)
So i solved considering that.. LOL
bushra, can u pls confirm the question...
Thanks guys!