A box contains 10 pairs of shoes (20 shoes in total). If two shoes are selected at random, what it is the probability that they are matching shoes?
1/190
1/20
1/19
1/10
1/9
OA:C
Please see my method:
...................................................
Numerator:
Out of 20 shoes we have to select one shoe first..w/o any restrictions.So that's 20C1 (choosing one out of 20).
Now,the second show has to be the matching shoe.There is only ONE such possible shoe,so the probability of choosing that shoe is 1.
Denominator:
Chosing 2 shoes out of 20.So, 20C2
20C1/20C2 = 2/19
please explain:(
probability that they are matching shoes?
This topic has expert replies
-
- Master | Next Rank: 500 Posts
- Posts: 447
- Joined: Sun Apr 19, 2009 9:08 pm
- Location: Kolkata,India
- Thanked: 7 times
- GMAT Score:670
-
- Master | Next Rank: 500 Posts
- Posts: 399
- Joined: Wed Apr 15, 2009 3:48 am
- Location: india
- Thanked: 39 times
i am getting altogether a diff ansuptowngirl92 wrote:A box contains 10 pairs of shoes (20 shoes in total). If two shoes are selected at random, what it is the probability that they are matching shoes?
1/190
1/20
1/19
1/10
1/9
OA:C
Please see my method:
...................................................
Numerator:
Out of 20 shoes we have to select one shoe first..w/o any restrictions.So that's 20C1 (choosing one out of 20).
Now,the second show has to be the matching shoe.There is only ONE such possible shoe,so the probability of choosing that shoe is 1.
Denominator:
Chosing 2 shoes out of 20.So, 20C2
20C1/20C2 = 2/19
please explain:(
my approah
desiarble cases=20*1
total cases=20*19
p=1/19
???
It does not matter how many times you get knocked down , but how many times you get up
- ssmiles08
- Master | Next Rank: 500 Posts
- Posts: 472
- Joined: Sun Mar 29, 2009 6:54 pm
- Thanked: 56 times
Firstly, you are choosing two shoes out of 20. and 2 of them have be from the same pair.
2C2/20C2 = 1/190
next, you have 10 different pairs. So there are 10 more possible ways you can get a pair of shoes.
so it is 1/190 * 10 = 1/19 (C)
2C2/20C2 = 1/190
next, you have 10 different pairs. So there are 10 more possible ways you can get a pair of shoes.
so it is 1/190 * 10 = 1/19 (C)
You got a dream... You gotta protect it. People can't do somethin' themselves, they wanna tell you you can't do it. If you want somethin', go get it. Period.
-
- Junior | Next Rank: 30 Posts
- Posts: 10
- Joined: Wed Oct 21, 2009 2:17 am
- Location: New Delhi
- Thanked: 3 times
I did a slightly different calculation.
probability of selecting the first shoe - 1
probaility of selecting the second shoe such that it forms a pair with the first one - 1/19
total probability - 1*1/19 = 1/19
probability of selecting the first shoe - 1
probaility of selecting the second shoe such that it forms a pair with the first one - 1/19
total probability - 1*1/19 = 1/19
I did it the same way as jaspreet. Just try to understand what's going on.
You have 20 shoes, and are looking for a matching pair. The first shoe you take could be anyone, so probability of getting one shoe is 1. Now, you took 1 shoe out of the 20 original, and you have 19 left, but there is only 1 shoe in the 19 that matches the first one. So the probability to get the matching shoe is 1/19.
So multiply your probabilities: 1 * 1/19 = 1/19
You have 20 shoes, and are looking for a matching pair. The first shoe you take could be anyone, so probability of getting one shoe is 1. Now, you took 1 shoe out of the 20 original, and you have 19 left, but there is only 1 shoe in the 19 that matches the first one. So the probability to get the matching shoe is 1/19.
So multiply your probabilities: 1 * 1/19 = 1/19
-
- Senior | Next Rank: 100 Posts
- Posts: 40
- Joined: Mon Feb 16, 2009 8:50 pm
- Thanked: 3 times
here is the way of how I solved it
Right, Left - legs
you have 10 Rs and 10 Ls
Prob of choosing R out of 20, then matching pair L from rest : 10/20 * 1/19 = 1/38.
similarly you can choose L first then R, hence 1/38 * 2 = 1/19.
Right, Left - legs
you have 10 Rs and 10 Ls
Prob of choosing R out of 20, then matching pair L from rest : 10/20 * 1/19 = 1/38.
similarly you can choose L first then R, hence 1/38 * 2 = 1/19.
GMAT/MBA Expert
- Ian Stewart
- GMAT Instructor
- Posts: 2621
- Joined: Mon Jun 02, 2008 3:17 am
- Location: Montreal
- Thanked: 1090 times
- Followed by:355 members
- GMAT Score:780
Jaspreet's solution above is the one I use for similar problems - it's very fast. Still, it's perfectly possible to solve as you've done above, provided you are consistent in how you count the numerator and denominator. In your solution above, when you count the number of selections for the numerator, you are assuming that order matters (you have a 'first shoe' and a 'second shoe'), but when you count the number of selections for the denominator, you are assuming that order does *not* matter - 20C2 means 'the number of ways to choose 2 things from 20 if the order is *not* important'.uptowngirl92 wrote: Numerator:
Out of 20 shoes we have to select one shoe first..w/o any restrictions.So that's 20C1 (choosing one out of 20).
Now,the second show has to be the matching shoe.There is only ONE such possible shoe,so the probability of choosing that shoe is 1.
Denominator:
Chosing 2 shoes out of 20.So, 20C2
20C1/20C2 = 2/19
please explain:(
It doesn't matter which perspective you take - you can think of selecting a first shoe, then a second, so order matters, or you can think of selecting both shoes at once, so order doesn't matter, but you must be absolutely sure you count the numerator and denominator in the same way: if you assume order matters when working out the numerator, you must assume it matters when you work out the denominator. So, if you assume order matters, you get, as you found above, 20 for the numerator, and 20*19 for the denominator (20 choices for the first shoe, 19 for the second). If you assume order does not matter, then there are 10 pairs we could choose that give the result we want, and 20C2 ways to choose two shoes. In either case, if you divide you'll get the answer: 20/(20*19) = 10/20C2 = 1/19.
For online GMAT math tutoring, or to buy my higher-level Quant books and problem sets, contact me at ianstewartgmat at gmail.com
ianstewartgmat.com
ianstewartgmat.com
-
- Junior | Next Rank: 30 Posts
- Posts: 12
- Joined: Sat May 19, 2007 8:59 am
- Thanked: 1 times
20/20 * 1/19 = 1/19
for the first shoe, you can take any out of 20. so probability = 20/20
haven chosen the shoe, we are left with only 1 matching shoe out of the remaining 19, so probability = 1/19
hth.