Hi everybody,
here is one question:
Three cards are chosen at rendom from a desk without replacement. what is the probability of getting a jack, a tan and a nine in order?
1. 8\16575
2. 1\2197
3. 6\35152
4. none of the above
Thanks
probability
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Well..even I am scared of probability
But Now I have started getting the feel about it.
The best way when you get such problems where you are taking out something and not putting back then the number at the bottom will decrease by one which is your sample space. In this case it is the total no of cards or you may even have balls in a bag.
Next is how many jacks out of the total are there in the deck it is 4 so your probability for the first time will be: you will get any 4 out of total 52.
So probability of getting jack is 4/52.
now you have to ppick ten but the number of cards have reduced by 1.
So probability will 4 out 51 i.e 4/51.
Similarly the next will Nine 4/50.
so the total probability will be a product of these.
4/52*4/51*4/50
Thanks
Komal
But Now I have started getting the feel about it.
The best way when you get such problems where you are taking out something and not putting back then the number at the bottom will decrease by one which is your sample space. In this case it is the total no of cards or you may even have balls in a bag.
Next is how many jacks out of the total are there in the deck it is 4 so your probability for the first time will be: you will get any 4 out of total 52.
So probability of getting jack is 4/52.
now you have to ppick ten but the number of cards have reduced by 1.
So probability will 4 out 51 i.e 4/51.
Similarly the next will Nine 4/50.
so the total probability will be a product of these.
4/52*4/51*4/50
Thanks
Komal