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by djsir007 » Sun Apr 22, 2007 4:06 am
The lunch menu at a certain resturaunt contains 4 different entrees and 5 different sides. A meal consists of 1 entree and 2 different sides. How many different meal combinations are there?
10
20
40
80
100

I swear I got this one, but the answer key says I didnt.
I also searched for previous posts and did not find it.
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Junior | Next Rank: 30 Posts
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by djsir007 » Sun Apr 22, 2007 4:24 am
I just realized what I did.

4 entrees X ((5 sides X 4 sides)/2! duplicate permutations) = 40
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by rajeshvellanki » Sun Apr 22, 2007 9:54 am
4c1 x 5c2 =40
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by Cybermusings » Sun Apr 22, 2007 11:42 pm
4C1*5C2 = 4*5*2 = 40
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