absolute value DS

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absolute value DS

by nikhilagrawal » Thu Oct 16, 2008 7:12 am
If x is not equal to 0, is |x| less than 1?

(1) x/|x| < x

(2) |x| > x

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by loki.gmat » Thu Oct 16, 2008 11:56 am
IMO D.

1) x/lxl < x
x < x*lxl
1 < lxl. hence sufficient.

2) lxl > x
only possible if x<0. hence sufficient.



Thanks!

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Re: absolute value DS

by parallel_chase » Thu Oct 16, 2008 1:09 pm
nikhilagrawal wrote:If x is not equal to 0, is |x| less than 1?

(1) x/|x| < x

(2) |x| > x

Statement I
x/lxl < x

x < x*lxl

if x is positive, lxl > 1

if x is negative, lxl < 1, since x is negative 0 > x > -1


Insufficient.

Statement II
|x| > x

this simply implies that x is negative, therefore, lxl can be greater 1 or lxl can be less than 1

Insufficient.

Combining I & II
|x| > x
x< x*lxl

this means 0 > x > -1, therefore, lxl will always be less than 1.

Sufficient.

Hence C.

Hope this helps.
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by stop@800 » Thu Oct 16, 2008 10:32 pm
IMO also C

whats the OA?

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by maihuna » Mon Apr 13, 2009 10:18 am
it seems oa is c only

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by vittalgmat » Mon Apr 13, 2009 2:22 pm
C for me as well.
Important point is to consider x as real number not as an integer.