area of circular region
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Since 30,40 are the points on the circle, the distance from the origin to the point on the circle will be the radius.
r^2 = 30^2 + 40^2
r = sqrt 2500
r = 50
area = pi r^2 = 50^2 pi = 2500 pi.
Hence D.
r^2 = 30^2 + 40^2
r = sqrt 2500
r = 50
area = pi r^2 = 50^2 pi = 2500 pi.
Hence D.
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Good solution using the Pythagorean formula.parallel_chase wrote:Since 30,40 are the points on the circle, the distance from the origin to the point on the circle will be the radius.
r^2 = 30^2 + 40^2
r = sqrt 2500
r = 50
area = pi r^2 = 50^2 pi = 2500 pi.
Hence D.
We can shave some time off if we quickly recognize a 3x:4x:5x triangle in the mix. 3/4/5 is the most commonly tested Pythagorean triplet and almost always shows up in some form on test day.
As soon as you see that you have a 30/40/x right angle triangle, 50 should come to mind as the radius. Then calculate the area as above.
Other important triplets to know:
5x:12x:13x
x:x:xroot2 (right isosceles triangle)
x:xroot3:2x (30/60/90 triangle)
and less tested, but still comes up:
7x:24x:25x
Last edited by Stuart@KaplanGMAT on Thu Oct 16, 2008 12:59 pm, edited 1 time in total.
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