Q: Which of the following is equal to the value of
2^5+2^5+3^5+3^5+3^5
A) 5^6
B) 13^5
C) 2^6+3^6
D) 2^7+3^8
E) 4^5+9^5
what would be the right way to go about this ?
problem to solve
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Simplify it as
a+a+b+b+b
where a=2^5 and b=3^5
So the expression is 2a+3b = 2*2^5+3*3^5 = 2^6+3^6.
a+a+b+b+b
where a=2^5 and b=3^5
So the expression is 2a+3b = 2*2^5+3*3^5 = 2^6+3^6.
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Atult718 wrote:Q: Which of the following is equal to the value of
2^5+2^5+3^5+3^5+3^5
A) 5^6
B) 13^5
C) 2^6+3^6
D) 2^7+3^8
E) 4^5+9^5
2^5+2^5+3^5+3^5+3^5
2^5(1 + 1) + 3^5(1 + 1 + 1)
2^5(2) + 3^5(3)
2^6 + 3^6
Answer: C
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What we really have here is an algebra question requiring us to combine like terms.Atult718 wrote:Q: Which of the following is equal to the value of
2^5+2^5+3^5+3^5+3^5
A) 5^6
B) 13^5
C) 2^6+3^6
D) 2^7+3^8
E) 4^5+9^5
First, notice that K + K = 2K
Using the same logic, 2^5 + 2^5 = 2(2^5) = (2^1)(2^5) = 2^6
Similarly, notice that M + M + M = 3M
Using the same logic, 3^5 + 3^5 + 3^5 = 3(3^5) = (3^1)(3^5) = 3^6
So, 2^5 + 2^5 + 3^5 + 3^5 + 3^5 = 2^6 + 3^6
Answer: C
Cheers,
Brent