If n = 3k, is k an integer?
(1) n is an integer.
(2) n/6 is an integer.
A. Statement (1) ALONE is sufficient, but statement (2) alone is not sufficient.
B. Statement (2) ALONE is sufficient, but statement (1) alone is not sufficient.
C. BOTH statements TOGETHER are sufficient, but NEITHER statement ALONE is
sufficient.
D. EACH statement ALONE is sufficient.
E. Statements (1) and (2) TOGETHER are NOT sufficient.
Vishu
I wonder How B is the OA
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If n = 3k, is k an integer?
(1) n is an integer.
(2) n/6 is an integer
statement (1),
if k = 2, then 3x2 = 6 = integer
if k = 1/3, then 3 x 1/3 = 1 which means that n = 1 = integer
since k could be 2 or 1/3, then this statement is not suff
statement (2), if n/6 = integer, then a good question to ask yourself is, what can n be? the only way for n/6 to be an integer is if n = an integer. so n must equal some multiple of 6. when you plug any multiple of 6 into the equation n=3k, then k = integer.
(1) n is an integer.
(2) n/6 is an integer
statement (1),
if k = 2, then 3x2 = 6 = integer
if k = 1/3, then 3 x 1/3 = 1 which means that n = 1 = integer
since k could be 2 or 1/3, then this statement is not suff
statement (2), if n/6 = integer, then a good question to ask yourself is, what can n be? the only way for n/6 to be an integer is if n = an integer. so n must equal some multiple of 6. when you plug any multiple of 6 into the equation n=3k, then k = integer.
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n/3=k
The question asked is whether k a integer or not
statement 1 tells that n is an integer...
Therefore n=1,2,3....etc
n/3=1/3,2/3,1...etc
So statement 1 is not sufficient
statement 2 tells that n/6 is an intege
Therefore n must be divisible by 6( i.e any multiple of 6 should satisfy this condition)
n=6,12,18,24...etc
n/6=1,2,3,4...etc
Therefore n/6 is an integer and hence statement 2 is sufficient..
The question asked is whether k a integer or not
statement 1 tells that n is an integer...
Therefore n=1,2,3....etc
n/3=1/3,2/3,1...etc
So statement 1 is not sufficient
statement 2 tells that n/6 is an intege
Therefore n must be divisible by 6( i.e any multiple of 6 should satisfy this condition)
n=6,12,18,24...etc
n/6=1,2,3,4...etc
Therefore n/6 is an integer and hence statement 2 is sufficient..