[GMAT math practice question]
5 boys and 5 girls randomly select seats around a circular table that seats 10. What is the probability that two girls will sit next to one another?
A. 11/24
B. 23/24
C. 23/48
D. 47/48
E. 125/126
5 boys and 5 girls randomly select seats around a circular t
This topic has expert replies
- Max@Math Revolution
- Elite Legendary Member
- Posts: 3991
- Joined: Fri Jul 24, 2015 2:28 am
- Location: Las Vegas, USA
- Thanked: 19 times
- Followed by:37 members
Timer
00:00
Your Answer
A
B
C
D
E
Global Stats
Math Revolution
The World's Most "Complete" GMAT Math Course!
Score an excellent Q49-51 just like 70% of our students.
[Free] Full on-demand course (7 days) - 100 hours of video lessons, 490 lesson topics, and 2,000 questions.
[Course] Starting $79 for on-demand and $60 for tutoring per hour and $390 only for Live Online.
Email to : [email protected]
- Max@Math Revolution
- Elite Legendary Member
- Posts: 3991
- Joined: Fri Jul 24, 2015 2:28 am
- Location: Las Vegas, USA
- Thanked: 19 times
- Followed by:37 members
=>
The easiest way to solve this problem is to find the number of arrangements satisfying the complementary condition that boys and girls are arranged alternately around the table, and subtract this from the total number of arrangements of the boys and girls.
The number of arrangements of n people in a circle is (n-1)!.
So, the total number of arrangements of 10 people is (10-1)! = 9!
The number of complementary arrangements is (5-1)!*5! = 4!*5!
Thus, the required probability is 1 - [(4!)(5!)]/(9!) = 1 - [(1*2*3*4)/(6*7*8*9)] = 1 - 1/126 = 125/126
Therefore, E is the answer.
Answer: E
The easiest way to solve this problem is to find the number of arrangements satisfying the complementary condition that boys and girls are arranged alternately around the table, and subtract this from the total number of arrangements of the boys and girls.
The number of arrangements of n people in a circle is (n-1)!.
So, the total number of arrangements of 10 people is (10-1)! = 9!
The number of complementary arrangements is (5-1)!*5! = 4!*5!
Thus, the required probability is 1 - [(4!)(5!)]/(9!) = 1 - [(1*2*3*4)/(6*7*8*9)] = 1 - 1/126 = 125/126
Therefore, E is the answer.
Answer: E
Math Revolution
The World's Most "Complete" GMAT Math Course!
Score an excellent Q49-51 just like 70% of our students.
[Free] Full on-demand course (7 days) - 100 hours of video lessons, 490 lesson topics, and 2,000 questions.
[Course] Starting $79 for on-demand and $60 for tutoring per hour and $390 only for Live Online.
Email to : [email protected]
-
- Legendary Member
- Posts: 2214
- Joined: Fri Mar 02, 2018 2:22 pm
- Followed by:5 members
Circular arrangement of 5 boys and 5 girls=
$$\left(n-1\right)!=\left[\left(5+5\right)-1\right]!=\left[10-1\right]!=9!$$
Where 2/more girls do not sit together =
Ways in which boys can be seated * ways in which boys can be seated.
with the boys going first, they can be seated in 4! ways and the girls can be seated in 5! ways.
Total number of ways 10 people could be seated round the circular table = 9!
The probability =
$$=\frac{9!-4!\cdot5!}{9!}$$
$$=\frac{\left(9\cdot8\cdot7\cdot---\cdot1\right)-\left(4\cdot3\cdot2\cdot1\right)\cdot\left(5\cdot4\cdot3\cdot2\cdot1\right)}{\left(9\cdot8\cdot7\cdot-------\cdot1\right)}$$
$$=\frac{\left(362880\right)-\left(24\cdot120\right)}{362880}$$
$$=\frac{\left(360000\right)}{362880}=\frac{125}{126}$$
$$answer\ is\ Option\ E$$
$$\left(n-1\right)!=\left[\left(5+5\right)-1\right]!=\left[10-1\right]!=9!$$
Where 2/more girls do not sit together =
Ways in which boys can be seated * ways in which boys can be seated.
with the boys going first, they can be seated in 4! ways and the girls can be seated in 5! ways.
Total number of ways 10 people could be seated round the circular table = 9!
The probability =
$$=\frac{9!-4!\cdot5!}{9!}$$
$$=\frac{\left(9\cdot8\cdot7\cdot---\cdot1\right)-\left(4\cdot3\cdot2\cdot1\right)\cdot\left(5\cdot4\cdot3\cdot2\cdot1\right)}{\left(9\cdot8\cdot7\cdot-------\cdot1\right)}$$
$$=\frac{\left(362880\right)-\left(24\cdot120\right)}{362880}$$
$$=\frac{\left(360000\right)}{362880}=\frac{125}{126}$$
$$answer\ is\ Option\ E$$