Thanks
I had 4 as answer. Can someone please elaborate on the answer explanation.
Khurram
A certain square is to be drawn on a coordinate plane. One of the vertices must be on the origin, and the square is to have an area of 100. If all coordinates of the vertices must be integers, how many different ways can this square be drawn?
4
6
8
10
12
Each side of the square must have a length of 10. If each side were to be 6, 7, 8, or most other numbers, there could only be four possible squares drawn, because each side, in order to have integer coordinates, would have to be drawn on the x- or y-axis. What makes a length of 10 different is that it could be the hypotenuse of a Pythagorean triple, meaning the vertices could have integer coordinates without lying on the x- or y-axis.
For example, a square could be drawn with the coordinates (0,0), (6,8), (-2, 14) and (-8, 6). (It is tedious and unnecessary to figure out all four coordinates for each square).
If we label the square abcd, with a at the origin and the letters representing points in a clockwise direction, we can get the number of possible squares by figuring out the number of unique ways ab can be drawn.
a has coordinates (0,0) and b could have the following coordinates, as shown in the picture:
(-10,0)
(-8,6)
(-6,8)
(0,10)
(6,8)
(8,6)
(10,0)
(8, -6)
(6, -8)
(0, 10)
(-6, -8)
(-8, -6)
There are 12 different ways to draw ab, and so there are 12 ways to draw abcd.
The correct answer is E.
Hard MGMAT 700-800 level question. Co-ordinate plane
- Stuart@KaplanGMAT
- GMAT Instructor
- Posts: 3225
- Joined: Tue Jan 08, 2008 2:40 pm
- Location: Toronto
- Thanked: 1710 times
- Followed by:614 members
- GMAT Score:800
If you don't have smileys disabled (box you can click under the message that you type), if you ever type 8 followed by a closed bracket you'll get 8)aas550 wrote:Can someone explain this me in a different way?
What does smiley stand for?
Thanks
Stuart Kovinsky | Kaplan GMAT Faculty | Toronto
Kaplan Exclusive: The Official Test Day Experience | Ready to Take a Free Practice Test? | Kaplan/Beat the GMAT Member Discount
BTG100 for $100 off a full course
-
- Legendary Member
- Posts: 631
- Joined: Mon Feb 18, 2008 11:57 pm
- Thanked: 29 times
- Followed by:3 members
An alternative way to think about this:
1. There are 4 quadrants we need to draw the squares in so if you find the number of square vertices possible in 1 quadrants , you can just multiple that with 4 to get the answer
2. The area of the sq = 100 so if a side is s then s^2 = 100 and for this to be possible s =10
3. Rephrasing the problem:
to get s = 10 the co-ordinates of each side of the square should be at a distance of 10 from (0,0)
lets say the vertices of sq are at (x,y), using the distance formula
x^2 + y^2 = 10^2
Since we know both x,y are integers the only possible values for x,y in quadrants I are
(0,10), (10,0) (8,6) (6,8)
Out of these possibilities (0,10) and (10,0) lie on the same sq so it means we can have 3 unique possibilities
so total = 4*3 = 12
1. There are 4 quadrants we need to draw the squares in so if you find the number of square vertices possible in 1 quadrants , you can just multiple that with 4 to get the answer
2. The area of the sq = 100 so if a side is s then s^2 = 100 and for this to be possible s =10
3. Rephrasing the problem:
to get s = 10 the co-ordinates of each side of the square should be at a distance of 10 from (0,0)
lets say the vertices of sq are at (x,y), using the distance formula
x^2 + y^2 = 10^2
Since we know both x,y are integers the only possible values for x,y in quadrants I are
(0,10), (10,0) (8,6) (6,8)
Out of these possibilities (0,10) and (10,0) lie on the same sq so it means we can have 3 unique possibilities
so total = 4*3 = 12
-
- Senior | Next Rank: 100 Posts
- Posts: 76
- Joined: Sun Jul 20, 2008 10:47 am
- Location: new york city
- Thanked: 1 times
-
- Senior | Next Rank: 100 Posts
- Posts: 30
- Joined: Fri Jun 27, 2008 6:41 am
- Location: Montreal
Hi,
I'm a bit confused about this part:
to get s = 10 the co-ordinates of each side of the square should be at a distance of 10 from (0,0)
lets say the vertices of sq are at (x,y), using the distance formula
x^2 + y^2 = 10^2
Since we know both x,y are integers the only possible values for x,y in quadrants I are
(0,10), (10,0) (8,6) (6,8 )
If the coordinate needs to be 10 units away from (0,0), how does the vertice (8,6) or (6,8 ) come into play? i.e. 8^2*6^2 = 10^2
but how does the pythagorean principle come into play if we're just talking sides of the square?
thanks,
r
I'm a bit confused about this part:
to get s = 10 the co-ordinates of each side of the square should be at a distance of 10 from (0,0)
lets say the vertices of sq are at (x,y), using the distance formula
x^2 + y^2 = 10^2
Since we know both x,y are integers the only possible values for x,y in quadrants I are
(0,10), (10,0) (8,6) (6,8 )
If the coordinate needs to be 10 units away from (0,0), how does the vertice (8,6) or (6,8 ) come into play? i.e. 8^2*6^2 = 10^2
but how does the pythagorean principle come into play if we're just talking sides of the square?
thanks,
r
-
- Master | Next Rank: 500 Posts
- Posts: 353
- Joined: Sat Jan 20, 2007 1:29 am
- Location: Italy
- Thanked: 7 times
- GMAT Score:720
can somebody explain how and why we find 8,6 and 6,8?
Beat The GMAT - 1st priority
Enter a top MBA program - 2nd priority
Loving my wife: MOST IMPORTANT OF ALL!
REAL THING 1 (AUG 2007): 680 (Q43, V40)
REAL THING 2 (APR 2009): 720 (Q47, V41)
Enter a top MBA program - 2nd priority
Loving my wife: MOST IMPORTANT OF ALL!
REAL THING 1 (AUG 2007): 680 (Q43, V40)
REAL THING 2 (APR 2009): 720 (Q47, V41)
-
- Master | Next Rank: 500 Posts
- Posts: 418
- Joined: Wed Jun 11, 2008 5:29 am
- Thanked: 65 times
I think its best to use a diagram to illustrate this.mjjking wrote:can somebody explain how and why we find 8,6 and 6,8?
We know that each of the sides of the square is 10. If you drew a line from the origin to point A(10, 0), you have a line of length 10. You can form a (red) square using this line as the basis.
Now, move point A anti-clock wise (with the other end of the line fixed to the origin).Notice the right-angled triangle that is formed with OA' and the x-axis. With the hypoteneus equal to 10, the only possible integer combinations for the height and base of this triangle is 6 and 8 (remember the 6-8-10 triangle). With OA', you have height = 6, base =8, and you will be able to form a (blue) square.
You can also move point A' to A'' and construct a triangle with OA'' and the x-axis. The other combination for the height and base is 8 and 6, respectively. And with this you have another (green) square.
If you repeat this for the other quadrants, you will have a total of 3x4 squares = 12 squares.
-BM-
- Attachments
-
- 12_Squares.doc
- (22.5 KiB) Downloaded 343 times
why we have to take points 6, 8 .( we know that side of square is 10 )please correct me
bluementor wrote:I think its best to use a diagram to illustrate this.mjjking wrote:can somebody explain how and why we find 8,6 and 6,8?
We know that each of the sides of the square is 10. If you drew a line from the origin to point A(10, 0), you have a line of length 10. You can form a (red) square using this line as the basis.
Now, move point A anti-clock wise (with the other end of the line fixed to the origin).Notice the right-angled triangle that is formed with OA' and the x-axis. With the hypoteneus equal to 10, the only possible integer combinations for the height and base of this triangle is 6 and 8 (remember the 6-8-10 triangle). With OA', you have height = 6, base =8, and you will be able to form a (blue) square.
You can also move point A' to A'' and construct a triangle with OA'' and the x-axis. The other combination for the height and base is 8 and 6, respectively. And with this you have another (green) square.
If you repeat this for the other quadrants, you will have a total of 3x4 squares = 12 squares.
-BM-
-
- Senior | Next Rank: 100 Posts
- Posts: 58
- Joined: Tue Nov 24, 2009 2:23 pm
- Thanked: 1 times
GMAT/MBA Expert
- Whitney Garner
- GMAT Instructor
- Posts: 273
- Joined: Tue Sep 21, 2010 5:37 am
- Location: Raleigh, NC
- Thanked: 154 times
- Followed by:74 members
- GMAT Score:770
A couple of notes on this one. I think everyone is comfortable with the fact that the square must have sides of length 10, so I will ignore that.khurram wrote: A certain square is to be drawn on a coordinate plane. One of the vertices must be on the origin, and the square is to have an area of 100. If all coordinates of the vertices must be integers, how many different ways can this square be drawn?
4
6
8
10
12
Good Guessing Strategy
- I can quickly sketch the 4 "easy" squares that sit on the axes, so 4 feels too easy - eliminate A.
- I can also see that anything I can draw in one coordinate will be mirrored in the other 3, so the answer must be a multiple of 4 - eliminate B and D.
- This just leaves C and E - not a bad guess if stuck (and that would only have taken a minute or so to do).
Actually Solving
The problem gives us a square in a coordinate plane so step 1 should be to sketch something. I would draw at least one of the "easy" squares (the ones that sit on the axes), but then start to think about rotating it. The side length 10 becomes a distance from the origin = This should be sending off a beacon for you to use Pythagorean Theorem rules. Add to that the fact that the vertices have to be integers = which right triangles have integer side lengths?? AH thats right, the Pythagorean triples.
We should have committed the first few iterations of the 3-4-5 triangle to memory, so hypotenuse 10 would be the 6-8-10 triangle. We just need to use the coordinates (6,8) or (8,6) to see if our hunch is correct. Draw one (see image attached).
Now, I chose to make the x-axis length 8 (using the coordinate (8,6) as the vertices), but I could have just as easily picked (6,8). So that means there are 2 of these "weird" squares in each quadrant - so 8 of those when I mirror them around. And then the 4 "easy" squares. Total = 12.
Whit
Whitney Garner
GMAT Instructor & Instructor Developer
Manhattan Prep
Contributor to Beat The GMAT!
Math is a lot like love - a simple idea that can easily get complicated
GMAT Instructor & Instructor Developer
Manhattan Prep
Contributor to Beat The GMAT!
Math is a lot like love - a simple idea that can easily get complicated
- GMATGuruNY
- GMAT Instructor
- Posts: 15539
- Joined: Tue May 25, 2010 12:04 pm
- Location: New York, NY
- Thanked: 13060 times
- Followed by:1906 members
- GMAT Score:790
Step 1: If area = 100, side = 10.A certain square is to be drawn on a coordinate plane. One of the vertices must be on the origin, and the square is to have an area of 100. If all coordinates of the vertices must be integers, how many different ways can this square be drawn?
A)4
B)6
C)8
D)10
E)12
Step 2: Recognize that the hypotenuse of a 6-8-10 triangle is 10.
Step 3: Plot coordinate pairs using every possible combination of (±6,±8), (±8,±6),(0,±10) and (±10,0).
Step 4: Using the plotted points, draw sets of squares centered about the origin. The following sets are possible:
Number of possible squares = 12.
The correct answer is E.
Private tutor exclusively for the GMAT and GRE, with over 20 years of experience.
Followed here and elsewhere by over 1900 test-takers.
I have worked with students based in the US, Australia, Taiwan, China, Tajikistan, Kuwait, Saudi Arabia -- a long list of countries.
My students have been admitted to HBS, CBS, Tuck, Yale, Stern, Fuqua -- a long list of top programs.
As a tutor, I don't simply teach you how I would approach problems.
I unlock the best way for YOU to solve problems.
For more information, please email me (Mitch Hunt) at [email protected].
Student Review #1
Student Review #2
Student Review #3
Followed here and elsewhere by over 1900 test-takers.
I have worked with students based in the US, Australia, Taiwan, China, Tajikistan, Kuwait, Saudi Arabia -- a long list of countries.
My students have been admitted to HBS, CBS, Tuck, Yale, Stern, Fuqua -- a long list of top programs.
As a tutor, I don't simply teach you how I would approach problems.
I unlock the best way for YOU to solve problems.
For more information, please email me (Mitch Hunt) at [email protected].
Student Review #1
Student Review #2
Student Review #3
-
- Newbie | Next Rank: 10 Posts
- Posts: 4
- Joined: Sat Jul 02, 2011 9:00 am
GMATGuruNY wrote:Step 1: If area = 100, side = 10.A certain square is to be drawn on a coordinate plane. One of the vertices must be on the origin, and the square is to have an area of 100. If all coordinates of the vertices must be integers, how many different ways can this square be drawn?
A)4
B)6
C)8
D)10
E)12
Step 2: Recognize that the hypotenuse of a 6-8-10 triangle is 10.
Step 3: Plot coordinate pairs using every possible combination of (±6,±8), (±8,±6),(0,±10) and (±10,0).
Step 4: Using the plotted points, draw sets of squares centered about the origin. The following sets are possible:
Number of possible squares = 12.
The correct answer is E.
Hi ,
In the above diagram you have shown the centre of the square on the origin but in the problem it is mentioned that one of the vertices must be on the origin ?
-
- Senior | Next Rank: 100 Posts
- Posts: 87
- Joined: Sat Feb 28, 2009 7:01 am
- Location: India
- Thanked: 2 times
Sorry to bring up the old post..but somehow I am not able to get the solution.. request you to please clarify my below doubts -
1- I understand that we are employing Pythagorean triplets, but I am not been able to follow how that triplets will help me in solving/understanding that all other points will be integer.
Please explain
1- I understand that we are employing Pythagorean triplets, but I am not been able to follow how that triplets will help me in solving/understanding that all other points will be integer.
Please explain