Source: Manhattan Prep
\(8, 5, x, 6\)
The median of the list of positive integers above is 5.5. Which of the following could be the average (arithmetic mean) of the list?
A. 3
B. 5.5
C. 6.25
D. 7
E. 7.5
The OA is B
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8, 5, x, 6 The median of the list of positive integers
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BTGmoderatorLU
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Brent@GMATPrepNow
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Since there is an even number of values in the list, the median will be the AVERAGE of the two middlemost values (when all values are listed in ASCENDING order)BTGmoderatorLU wrote:Source: Manhattan Prep
\(8, 5, x, 6\)
The median of the list of positive integers above is 5.5. Which of the following could be the average (arithmetic mean) of the list?
A. 3
B. 5.5
C. 6.25
D. 7
E. 7.5
The OA is B
Let's the answer choices...
A) If x = 3, then the values are {3, 5, 6, 8}, which means the median = (5 + 6)/2 = 5.5
NO GOOD. We want the median to be greater than 5.5
ELIMINATE A
B) If x = 5.5, then the values are {5, 5.5, 6, 8}, which means the median = (5.5 + 6)/2 = 5.75
Perfect! The median IS greater than 5.5
Answer: B
Cheers,
Brent
Brent Hanneson - Creator of GMATPrepNow.com
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deloitte247
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Median = 5.5, find the mean
$$Median\ =\ \frac{\left(5+x\right)}{2}$$
Median = 5,5 ; $$x\ must\ be\ \le5$$
$$list\ =\ x,\ 5,\ 6,\ 8$$
$$median\ =\ \frac{\left(5+6\right)}{2}=5.5$$
$$x=\left\{5,\ 4,\ 3,\ 2,\ or\ 1\right\}$$
If x = 5
$$mean\ =\ \frac{\left(5+5+6+8\right)}{4}=\frac{24}{4}=6\ \left\{wrong\right\}$$
if x = 4
$$mean\ =\frac{\left(4+5+6+8\right)}{4}=\frac{23}{4}=5.75\ \left\{wrong\right\}$$
if x = 3
$$mean\ =\frac{\left(3+5+6+8\right)}{4}=\frac{22}{4}=5.5$$
$$5.5\ is\ in\ Option\ B$$
$$Median\ =\ \frac{\left(5+x\right)}{2}$$
Median = 5,5 ; $$x\ must\ be\ \le5$$
$$list\ =\ x,\ 5,\ 6,\ 8$$
$$median\ =\ \frac{\left(5+6\right)}{2}=5.5$$
$$x=\left\{5,\ 4,\ 3,\ 2,\ or\ 1\right\}$$
If x = 5
$$mean\ =\ \frac{\left(5+5+6+8\right)}{4}=\frac{24}{4}=6\ \left\{wrong\right\}$$
if x = 4
$$mean\ =\frac{\left(4+5+6+8\right)}{4}=\frac{23}{4}=5.75\ \left\{wrong\right\}$$
if x = 3
$$mean\ =\frac{\left(3+5+6+8\right)}{4}=\frac{22}{4}=5.5$$
$$5.5\ is\ in\ Option\ B$$
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Scott@TargetTestPrep
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Let's analyze the given choices.BTGmoderatorLU wrote:Source: Manhattan Prep
\(8, 5, x, 6\)
The median of the list of positive integers above is 5.5. Which of the following could be the average (arithmetic mean) of the list?
A. 3
B. 5.5
C. 6.25
D. 7
E. 7.5
The OA is B
A) 3
If the average is 3, then we have:
(8 + 5 + x + 6)/4 = 3
19 + x = 12
x = -7
We see that the list {-7, 5, 6, 8} does have a median of 5.5, however, the problem says all the integers in the list are positive. So x can't be -7, which means the average can't be 3 either.
B) 5.5
If the average is 5.5, then we have:
(8 + 5 + x + 6)/4 = 5.5
19 + x = 22
x = 3
We see that the list {3, 5, 6, 8} does have a median of 5.5 and all the integers in the list are positive. So x can be 3, which means the average can be 5.5 also.
Answer: B
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