With # and & each representing different digits in the problem below, the difference between #&& and ## is 667. What is the value of &?
#&&
- ##
_____
667
(A) 3
(B) 4
(C) 5
(D) 8
(E) 9
[spoiler]OA=B[/spoiler]
Source: Veritas Prep
With # and & each representing different digits in the
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We're subtracting something between 10 and 99, and arriving at 667. So we must be subtracting from a number between 677 and 766, and the digit # could only be 6 or 7. But it can't be 6, because 6&& - 66 will never be equal to 667 (it could be at most 633), so # must be 7. So we have this problem:
7&& - 77 = 667
7&& = 667 + 77 = 744
and & = 4.
7&& - 77 = 667
7&& = 667 + 77 = 744
and & = 4.
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We see that # (in the hundreds digit) represents either 6 (if there is no borrowing from the tens digit) or 7 (if there is borrowing). However, no matter if it's 6 or 7, it's also the tens digit of the subtrahend, and since the tens digit of the difference is also 6, there must be borrowing. So # must be 7. In that case, & (in the tens digit) is either 3 or 4. It can be 3 and by borrowing from 7 (in the hundreds place) becomes 13 and 13 - 7 = 6 (if there is no borrow from the units digit). It can be 4 and by borrowing from 7 (in the hundreds place) and by lending 1 to the units digit becomes 13 and 13 - 7 = 6. We can see which one is correct by checking both cases:Gmat_mission wrote:With # and & each representing different digits in the problem below, the difference between #&& and ## is 667. What is the value of &?
#&&
- ##
_____
667
(A) 3
(B) 4
(C) 5
(D) 8
(E) 9
[
733 - 77 = 656 (This is not correct.)
744 - 77 = 667 (This is correct.)
Answer: B
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