If x and y are two-digit integers such that x > 40 and y<70, which of the following is closest to the maximum possible value of xy ?
(A) 700
(B) 2,800
(C) 4,000
(D) 7,000
(E) 28,000
[spoiler]OA=D[/spoiler].
How can I determine the correct answer here? If I don't know the value of x and y, how can I find a value of xy?
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If x and y are two-digit integers such that x > 40
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Gmat_mission
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Since x and y are two-digit integers such that x>40 and y<70:Gmat_mission wrote:If x and y are two-digit integers such that x > 40 and y<70, which of the following is closest to the maximum possible value of xy ?
(A) 700
(B) 2,800
(C) 4,000
(D) 7,000
(E) 28,000
40 < x ≤ 99.
10 ≤ y < 70.
Thus:
Maximum possible value for x = 99.
Maximum possible value for y = 69.
Maximum possible value for xy = 99*69 = (100-1)(70-1) ≈ 100*70 = 7000.
The correct answer is D.
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The maximum value of xy is 99 * 69, which is approximately 100 * 70 = 7,000.Gmat_mission wrote:If x and y are two-digit integers such that x > 40 and y<70, which of the following is closest to the maximum possible value of xy ?
(A) 700
(B) 2,800
(C) 4,000
(D) 7,000
(E) 28,000
Answer: D
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