Problem Solving

Hi LUANDATO,

We're told that a call center has two teams: each member of Team A was able to process 4/5 calls as compared to each member of Team B and Team A has 5/8 as many numbers of call center agents as Team B. We're asked for the fraction of the total calls that was processed by team B. This question can be solved by TESTing VALUES.

IF....
Team A = 5 members, Team B = 8 members
Team A = 4 calls/member, Team B = 5 calls/member

Total Calls = (5)(4) + (8)(5) = 20+40 = 60
Team B handles 40/60 = 2/3 of the calls

Final Answer: C

GMAT assassins aren't born, they're made,
Rich

BTGmoderatorLU wrote:A call center has two teams. Each member of team A was able to process 4/5 calls as compared to each member of team B. If team A has 5/8 as many numbers of call center agents as team B, what fraction of the total calls was processed by team B?

A. 3/2
B. 3/4
C. 2/3
D. 1/2
E. 1/5

The OA is C.

Let's assume that team B has 8 members and thus team A has 5 members. Furthermore, we can let each member in team B make 5 calls and thus each member in team A makes 4 calls.

Thus, team A makes 4 x 5 = 20 calls and team B makes 5 x 8 = 40 calls. So team B makes 40/60 = 2/3 of all the calls.

Answer: C

BTGmoderatorLU wrote:A call center has two teams. Each member of team A was able to process 4/5 calls as compared to each member of team B. If team A has 5/8 as many numbers of call center agents as team B, what fraction of the total calls was processed by team B?

A. 3/2
B. 3/4
C. 2/3
D. 1/2
E. 1/5

The OA is C.

Let's assume that team B has 8 members and thus team A has 5 members. Furthermore, we can let each member in team B make 5 calls and thus each member in team A makes 4 calls.

Thus, team A makes 4 x 5 = 20 calls and team B makes 5 x 8 = 40 calls. So team B makes 40/60 = 2/3 of all the calls.

Answer: C