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\[ \frac{19^2+19}{20}= \]

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\[ \frac{19^2+19}{20}= \]

by VJesus12 » Fri May 11, 2018 7:24 am

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$$\frac{19^2+19}{20}=$$ A. 19/10
B. 57/20
C. 19
D. 38
E. 361

The OA is the option C.

What is the fastest way to solve this PD question? May someone clarifies this to me? Thanks.
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192+1920=

by Brent@GMATPrepNow » Fri May 11, 2018 7:52 am
VJesus12 wrote:$$\frac{19^2+19}{20}=$$ A. 19/10
B. 57/20
C. 19
D. 38
E. 361
Notice that we can factor 19 from the numerator.

(19² + 19)/20 = (19)(19 + 1)/20
= (19)(20)/20
= 19

Answer: C

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Brent Hanneson - Creator of GMATPrepNow.com
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by Vincen » Fri May 11, 2018 8:07 am
VJesus12 wrote:$$\frac{19^2+19}{20}=$$ A. 19/10
B. 57/20
C. 19
D. 38
E. 361

The OA is the option C.

What is the fastest way to solve this PD question? May someone clarifies this to me? Thanks.
Hello Vjesus12.

Here the best way is taking 19 as a common factor as follows: $$\frac{19^2+19}{20}=\frac{19\left(19+1\right)}{20}=\frac{19\cdot20}{20}=19.$$ This way, we get the answer straightforward. Hence, the correct answer is the option C.

I hope this explanation may help you.
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by Scott@TargetTestPrep » Tue May 21, 2019 6:29 pm
VJesus12 wrote:$$\frac{19^2+19}{20}=$$ A. 19/10
B. 57/20
C. 19
D. 38
E. 361
The two terms in the numerator have a common factor of 19. Factoring it and simplifying, we have:

19(19 + 1)/20 = 19(20)/20 = 19

Answer: C

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