For how many integers \(n\) is \(n + n = n\cdot n?\)
a) None
b) One
c) Two
d) Three
e) More than three.
[spoiler]OA=C[/spoiler]
Source: Veritas Prep
For how many integers n is n + n = n*n?
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Hi Gmat_mission.
Let's rewrite the given expression as follows: $$n+n=n\cdot n$$ $$2n=n^2$$ $$n^2-2n=0$$ $$n\left(n-2\right)=0$$ Hence, the given equation is true when \(n=0\) and when \(n=2\).
So, there are two integers that satisfy the given equation. Hence, the correct answer is the option [spoiler]C) Two[/spoiler].
I hope it helps you. <i class="em em---1"></i>
Let's rewrite the given expression as follows: $$n+n=n\cdot n$$ $$2n=n^2$$ $$n^2-2n=0$$ $$n\left(n-2\right)=0$$ Hence, the given equation is true when \(n=0\) and when \(n=2\).
So, there are two integers that satisfy the given equation. Hence, the correct answer is the option [spoiler]C) Two[/spoiler].
I hope it helps you. <i class="em em---1"></i>
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Solving the equation, we have:Gmat_mission wrote:For how many integers \(n\) is \(n + n = n\cdot n?\)
a) None
b) One
c) Two
d) Three
e) More than three.
[spoiler]OA=C[/spoiler]
Source: Veritas Prep
2n = n^2
n^2 - 2n = 0
n(n - 2) = 0
n = 0 or n = 2
Answer: C
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