A line that passes through (-1, -4) and (3, k) has a slope = k. What is the value of k?
(A) 3/4
(B) 1
(C) 4/3
(D) 2
(E) 7/2
[spoiler]OA=C[/spoiler]
Source: Magoosh
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A line that passes through (–1, –4) and (3, k) has a slo
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Gmat_mission
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Scott@TargetTestPrep
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We can use the slope formula:Gmat_mission wrote:A line that passes through (-1, -4) and (3, k) has a slope = k. What is the value of k?
(A) 3/4
(B) 1
(C) 4/3
(D) 2
(E) 7/2
[spoiler]OA=C[/spoiler]
Source: Magoosh
[(k - (-4)]/(3 - (-1)) = k
(k + 4)/4 = k
k + 4 = 4k
4 = 3k
4/3 = k
Answer: C
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Brent@GMATPrepNow
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Slope of line between the points (x1, y1) and (x2, y2) = (y2 - y1)/(x2 - x1)Gmat_mission wrote:A line that passes through (-1, -4) and (3, k) has a slope = k. What is the value of k?
(A) 3/4
(B) 1
(C) 4/3
(D) 2
(E) 7/2
So, we can write: k = [k - (-4)]/[3 - (-1)]
Simplify: (k + 4)/4 = k
Multiply both sides by 4 to get: k + 4 = 4k
Subtract k from both sides to get: 4 = 3k
Divide both sides by 3 to get: 4/3 = k
Answer: C
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