The 9 squares above are to be filled with x's and o's
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From Statement 1, we know we have at least 5 O's, and therefore at most 4 X's.
From Statement 2, we know we have at least 4 X's, in the four corners.
Neither statement is sufficient, but using both, if we have at least 4 X's and at most 4 X's, we must have exactly 4 X's, and the two statements are sufficient together, so the answer is C.
From Statement 2, we know we have at least 4 X's, in the four corners.
Neither statement is sufficient, but using both, if we have at least 4 X's and at most 4 X's, we must have exactly 4 X's, and the two statements are sufficient together, so the answer is C.
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Hi All,
We're told that the 9 squares above are to be filled with X's and O's, with only one symbol in each square. We're asked for the number of squares that will contain an X. This question is based around some simple Arithmetic and logic - although you might find it useful to draw a few pictures to keep organized.
(1) MORE than 1/2 of the number of squares will contain an O.
In this prompt, you cannot have a 'fraction' of a square, so MORE than 1/2 of the 9 squares means AT LEAST 5 of the 9 squares will contain an O. This means that no more than 4 of the squares can hold an X, but that could be 0, 1, 2, 3 or 4 squares.
Fact 1 is INSUFFICIENT
(2) Each of the 4 corner squares will contain an X.
With the information in fact 2, we know that AT LEAST 4 of the squares (the 4 corner squares) will contain an X, but we don't know how many total squares will hold an X; it could be 4, 5, 6, 7, 8, or 9 squares.
Fact 2 is INSUFFICIENT
Combined, we know...
-More than 1/2 of the number of squares will contain an O.
-Each of the 4 corner squares will contain an X.
Based on the possibilities we defined in each of the two Facts, the only possible value that fits BOTH Facts is "4" (re: 4 X's in the four corners and 5 O's in the other squares).
Combined, SUFFICIENT
Final Answer: C
GMAT assassins aren't born, they're made,
Rich
We're told that the 9 squares above are to be filled with X's and O's, with only one symbol in each square. We're asked for the number of squares that will contain an X. This question is based around some simple Arithmetic and logic - although you might find it useful to draw a few pictures to keep organized.
(1) MORE than 1/2 of the number of squares will contain an O.
In this prompt, you cannot have a 'fraction' of a square, so MORE than 1/2 of the 9 squares means AT LEAST 5 of the 9 squares will contain an O. This means that no more than 4 of the squares can hold an X, but that could be 0, 1, 2, 3 or 4 squares.
Fact 1 is INSUFFICIENT
(2) Each of the 4 corner squares will contain an X.
With the information in fact 2, we know that AT LEAST 4 of the squares (the 4 corner squares) will contain an X, but we don't know how many total squares will hold an X; it could be 4, 5, 6, 7, 8, or 9 squares.
Fact 2 is INSUFFICIENT
Combined, we know...
-More than 1/2 of the number of squares will contain an O.
-Each of the 4 corner squares will contain an X.
Based on the possibilities we defined in each of the two Facts, the only possible value that fits BOTH Facts is "4" (re: 4 X's in the four corners and 5 O's in the other squares).
Combined, SUFFICIENT
Final Answer: C
GMAT assassins aren't born, they're made,
Rich
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From (1), more than half square contain an o means 5 or more squares contain an o. which means 0 to 4 squares can contain an X. This statement is NOT Sufficient.AbeNeedsAnswers wrote:
The 9 squares above are to be filled with x's and o's, with only one symbol in each square. How many of the squares will contain an x ?
(1) More than 1/2 of the number of squares will contain an o.
(2) Each of the 4 corner squares will contain an x.
C
Source: Official Guide 2020
From (2) If each corner square contains an X. Which means we have minimum of 4 out of 9 squares contining x. so 4 to 9 squares contain an x. this statement alone is NOT sfficient to answer the question.
Combining (1) and (2) We know that 5 squares contain an o and 4 corner squares contain an x . No other combination is possible. So both statements together are sufficient to answer the question.
Answer is C
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Given: The 9 squares above are to be filled with x's and o's, with only one symbol in each square.AbeNeedsAnswers wrote:
The 9 squares above are to be filled with x's and o's, with only one symbol in each square. How many of the squares will contain an x ?
(1) More than 1/2 of the number of squares will contain an o.
(2) Each of the 4 corner squares will contain an x.
C
Source: Official Guide 2020
Target question: How many of the squares will contain an x ?
Statement 1: More than 1/2 of the number of squares will contain an o.
This statement doesn't FEEL sufficient, so I'll TEST some values.
There are several scenarios that satisfy statement 1. Here are two:
Case a: There are 5 o's and 4 x's. In this case, the answer to the target question is 4 squares contain an x
Case b: There are 6 o's and 3 x's. In this case, the answer to the target question is 3 squares contain an x
Since we cannot answer the target question with certainty, statement 1 is NOT SUFFICIENT
Statement 2: Each of the 4 corner squares will contain an x.
There are several scenarios that satisfy statement 1. Here are two:
Case a: There are 5 o's and 4 x's. In this case, the answer to the target question is 4 squares contain an x
Case b: There are 4 o's and 5 x's. In this case, the answer to the target question is 5 squares contain an x
Since we cannot answer the target question with certainty, statement 2 is NOT SUFFICIENT
Statements 1 and 2 combined
Statement 1 tells us that the number of squares with an o = 5, 6, 7, 8 or 9, which means there are less than 5 squares with an x
Statement 2 tells us that there are at least 4 squares with an x
In other words: 4 ≤ (number of squares with an x) < 5
There is only one possible solution to the above inequality: x = 4
Since we can answer the target question with certainty, the combined statements are SUFFICIENT
Answer: C
Cheers,
Brent