For the 5 days shown in the graph, how many kilowatt-hours

For the 5 days shown in the graph, how many kilowatt-hours greater was the median daily electricity use than the average (arithmetic mean) daily electricity use?

A) 1
B) 2
C) 3
D) 4
E) 5

[spoiler]OA=A[/spoiler]

Source: GMAT Prep

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Brent@GMATPrepNow: GMAT Instructor; Posts: 16207; Joined: Mon Dec 08, 2008 6:26 pm; Location: Vancouver, BC; Thanked: 5254 times; Followed by:1268 members; GMAT Score:770

by Brent@GMATPrepNow » Sat Apr 20, 2019 4:40 am

VJesus12 wrote:

For the 5 days shown in the graph, how many kilowatt-hours greater was the median daily electricity use than the average (arithmetic mean) daily electricity use?

A) 1
B) 2
C) 3
D) 4
E) 5

[spoiler]OA=A[/spoiler]

Source: GMAT Prep

List the numbers in ASCENDING ORDER to get: 19, 24, 27, 29, 31.
So 27 is the median.

Average = (19 + 24 + 27 + 29 + 31)/5 = 130/5 = 26.

The median (27) is 1 greater than the average (26).

Answer: A

Cheers,
Brent

Brent Hanneson - Creator of GMATPrepNow.com

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swerve: Legendary Member; Posts: 2226; Joined: Sun Oct 29, 2017 2:04 pm; Followed by:6 members

by swerve » Sat Apr 20, 2019 10:05 am

Median of $19, 24, 27, 29$ and $31$ is $27$ (middle value in the list)

Mean $= \frac{19+24+27+29+31}{5} = \frac{130}{5}=26$

Difference $=27-26=1$

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Scott@TargetTestPrep: GMAT Instructor; Posts: 7240; Joined: Sat Apr 25, 2015 10:56 am; Location: Los Angeles, CA; Thanked: 43 times; Followed by:29 members

by Scott@TargetTestPrep » Thu Apr 25, 2019 5:52 pm

VJesus12 wrote:

For the 5 days shown in the graph, how many kilowatt-hours greater was the median daily electricity use than the average (arithmetic mean) daily electricity use?

A) 1
B) 2
C) 3
D) 4
E) 5

[spoiler]OA=A[/spoiler]

Source: GMAT Prep

Listing the numbers from smallest to largest, we have: 19, 24, 27, 29 and 31. So 27 is the median. The average is (19 + 24 + 27 + 29 + 31)/5 = 130/5 = 26. Therefore, the median exceeds the average by 1.

Answer: A

Scott Woodbury-Stewart
Founder and CEO
[email protected]

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