$$\sqrt{12}+\sqrt{108}+\sqrt{48}=$$
$$A.\ 12\sqrt{3}$$
$$B.\ 24$$
$$C.\ 12\sqrt{5}$$
$$D.\ 48\sqrt{3}$$
$$E.\ \sqrt{168}$$
[spoiler]OA=A[/spoiler]
Source: Veritas Prep
12^(1/2) + 108^(1/2) + 48^(1/2) =
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√12 + (√9 * √12) + (√4 * √12)M7MBA wrote:$$\sqrt{12}+\sqrt{108}+\sqrt{48}=$$
$$A.\ 12\sqrt{3}$$
$$B.\ 24$$
$$C.\ 12\sqrt{5}$$
$$D.\ 48\sqrt{3}$$
$$E.\ \sqrt{168}$$
= √12 + 3√12 + 2√12
= 6√12
= 6 * √4 * √ 3
= 12√3
The correct answer is A.
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Simplifying, we have:M7MBA wrote:$$\sqrt{12}+\sqrt{108}+\sqrt{48}=$$
$$A.\ 12\sqrt{3}$$
$$B.\ 24$$
$$C.\ 12\sqrt{5}$$
$$D.\ 48\sqrt{3}$$
$$E.\ \sqrt{168}$$
[spoiler]OA=A[/spoiler]
Source: Veritas Prep
√4 x √3 + √36 x √3 + √16 x √3
2√3 + 6√3 + 4√3 = 12√3
Answer: A
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