If y is the smallest positive integer such that 3,150 multiplied by y is the square of an integer, then y must be
A. 2
B. 5
C. 6
D. 7
E. 14
[spoiler]OA=E[/spoiler]
Source: Official Guide
If y is the smallest positive integer such that 3,150
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Key concept: The prime factorization of a perfect square (the square of an integer) will have an EVEN number of each prime.VJesus12 wrote:If y is the smallest positive integer such that 3,150 multiplied by y is the square of an integer, then y must be
A. 2
B. 5
C. 6
D. 7
E. 14
[spoiler]OA=E[/spoiler]
Source: Official Guide
For example, 36 = (2)(2)(3)(3)
And 400 = (2)(2)(2)(2)(5)(5)
Likewise, 3150y must have an EVEN number of each prime in its prime factorization.
So, 3150y = (2)(3)(3)(5)(5)(7)y
We have an EVEN number of 3's and 7's, but we have ONE 2 and ONE 7.
If y = (2)(7), then we get a perfect square.
That is: 3150y = (2)(2)(3)(3)(5)(5)(7)(7)
So, if y = 14, then 3150y is a perfect square.
Answer: E
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Brent
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This problem is testing us on the rule that when we express a perfect square by its unique prime factors, every prime factor's exponent is an even number.VJesus12 wrote:If y is the smallest positive integer such that 3,150 multiplied by y is the square of an integer, then y must be
A. 2
B. 5
C. 6
D. 7
E. 14
[spoiler]OA=E[/spoiler]
Source: Official Guide
Let's start by prime factorizing 3,150.
3,150 = 315 x 10 = 5 x 63 x 10 = 5 x 7 x 3 x 3 x 5 x 2
3,150 = 2^1 x 3^2 x 5^2 x 7^1
Notice that the exponents of both 2 and 7 are not even numbers. This tells us that 3,150 itself is not a perfect square. However, we are given that the product of 3,150 and y is a perfect square. Thus, we can write this as:
2^1 x 3^2 x 5^2 x 7^1 x y = square of an integer
According to our rule, we need all unique prime factors' exponents to be even numbers. Remember also that y is the smallest positive integer that makes 3150y a perfect square. Thus, we need one more 2 and one more 7. Therefore, y = 7 x 2 = 14
Answer: E
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