xy=?

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xy=?

by Max@Math Revolution » Mon Mar 18, 2019 11:17 pm

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[GMAT math practice question]

xy=?

1) (x-2)^2 = -|y-3|
2) |x-2| +√( y-3) =0

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by fskilnik@GMATH » Wed Mar 20, 2019 7:39 am

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Max@Math Revolution wrote:[GMAT math practice question]

xy=?

1) (x-2)^2 = -|y-3|
2) |x-2| +√( y-3) =0
$$? = xy$$
$$\left( 1 \right)\,\,\,{\left( {x - 2} \right)^2} = - \left| {y - 3} \right|\,\,\,\,\,\left( * \right)$$
$$\left. \matrix{
{\left( {x - 2} \right)^2} \ge 0 \hfill \cr
- \left| {y - 3} \right| \le 0\,\, \hfill \cr} \right\}\,\,\,\,\,\mathop \Rightarrow \limits^{\left( * \right)} \,\,\,\,\,\left\{ \matrix{
\,x - 2 = 0 \hfill \cr
\,y - 3 = 0 \hfill \cr} \right.\,\,\,\,\,\, \Rightarrow \,\,\,\,\,\left( {x,y} \right) = \left( {2,3} \right)\,\,\,\,\,\, \Rightarrow \,\,\,\,\,{\rm{SUFF}}{\rm{.}}$$
$$\left( 2 \right)\,\,\,\left| {x - 2} \right| + \sqrt {y - 3} \,\, = 0\,\,\,\,\,\,\left( {**} \right)$$
$$\left. \matrix{
\left| {x - 2} \right| \ge 0 \hfill \cr
\sqrt {y - 3} \ge 0\,\, \hfill \cr} \right\}\,\,\,\,\,\mathop \Rightarrow \limits^{\left( {**} \right)} \,\,\,\,\,\left\{ \matrix{
\,x - 2 = 0 \hfill \cr
\,y - 3 = 0 \hfill \cr} \right.\,\,\,\,\,\, \Rightarrow \,\,\,\,\,\left( {x,y} \right) = \left( {2,3} \right)\,\,\,\,\,\, \Rightarrow \,\,\,\,\,{\rm{SUFF}}{\rm{.}}$$


The correct answer is (D).


We follow the notations and rationale taught in the GMATH method.

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Fabio.
Fabio Skilnik :: GMATH method creator ( Math for the GMAT)
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by Max@Math Revolution » Thu Mar 21, 2019 1:13 am

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=>

Forget conventional ways of solving math questions. For DS problems, the VA (Variable Approach) method is the quickest and easiest way to find the answer without actually solving the problem. Remember that equal numbers of variables and independent equations ensure a solution.

The first step of the VA (Variable Approach) method is to modify the original condition and the question. We then recheck the question.

Condition 1)
(x-2)^2 = -|y-3|
=> (x-2)^2 + |y-3| = 0
=> x=2 and y = 3
Condition 1) is sufficient since it yields a unique solution.

Condition 2)
|x-2| + √(y-3) =0
=> x=2 and y = 3
Condition 2) is sufficient since it yields a unique solution.

Therefore, D is the answer.
Answer: D

FYI, Tip 1) of the VA method states that D is most likely to be the answer if conditions 1) and 2) provide the same information.