GMATH practice exercise (Quant Class 14)
What is the value of a+b ?
(1) a^2+ab−2a=91
(2) b^2+ab−2b=−28
Answer: [spoiler]____(E)__[/spoiler]
What is the value of a+b?
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Statements combined:fskilnik@GMATH wrote:GMATH practice exercise (Quant Class 14)
What is the value of a+b ?
(1) a^2+ab−2a=91
(2) b^2+ab−2b=−28
Adding the two equations, we get:
a² + b²+ 2ab - 2a - 2b = 63
(a+b)² - 2(a+b) = 63
(a+b)(a+b-2) = 63
Let x = a+b.
Substituting x=a+b into (a+b)(a+b-2) = 63, we get:
(x)(x-2) = 63
x² - 2x - 63 = 0
(x-9)(x+7) = 0
x=9 or x=-7
Since x=a+b, it is possible that a+b=9 or that a+b=-7.
Thus, the two statements combined are INSUFFICIENT.
The correct answer is E.
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$$? = a + b$$fskilnik@GMATH wrote:GMATH practice exercise (Quant Class 14)
What is the value of a+b ?
(1) a^2+ab−2a=91
(2) b^2+ab−2b=−28
$$\left( 1 \right)\,\,a\left( {a + b - 2} \right) = 91\,\,\,\,:\,:\,\,\,\left\{ \matrix{
\,{\rm{Take}}\,\,\left( {a,b} \right) = \left( {91,\, - 88} \right)\,\,\,\, \Rightarrow \,\,\,? = 3\,\, \hfill \cr
\,{\rm{Take}}\,\,\left( {a,b} \right) = \left( {1,92} \right)\,\,\,\, \Rightarrow \,\,\,? = 93\,\, \hfill \cr} \right.$$
$$\left( 2 \right)\,\,b\left( {a + b - 2} \right) = - 28\,\,\,:\,:\,\,\,\left\{ \matrix{
\,{\rm{Take}}\,\,\left( {a,b} \right) = \left( {31,\, - 28} \right)\,\,\,\, \Rightarrow \,\,\,? = 3\,\, \hfill \cr
\,{\rm{Take}}\,\,\left( {a,b} \right) = \left( { - 27,1} \right)\,\,\,\, \Rightarrow \,\,\,? = - 26\,\, \hfill \cr} \right.$$
$$\left( {1 + 2} \right)\,\,\,\,\,\left( 1 \right)\left( + \right)\left( 2 \right)\,\,\,\,\, \Rightarrow \,\,\,\,\left( {a + b - 2} \right)\left( {a + b} \right) = 63\,\,\,\, \Rightarrow \,\,\,\,{\left( {a + b} \right)^2} - 2\left( {a + b} \right) - 63 = 0$$
$$\left. \matrix{
{\rm{Sum}}:2 \hfill \cr
{\rm{Product}}: - 63\,\, \hfill \cr} \right\}\,\,\,\, \Rightarrow \,\,\,?\,\,\,\,:\,\,\,\,\,\left( {\rm{i}} \right)a + b = \,9\,\,\,\,\,{\rm{or}}\,\,\,\,\,\,\left( {{\rm{ii}}} \right)a + b\, = - 7\,\,\,\,\,\mathop \Rightarrow \limits^{\left( * \right)} \,\,\,\,\,\left( {\rm{E}} \right)\,$$
$$\left( * \right)\,\,{\rm{viability}}\,\,\,{\rm{:}}\,\,\,\,\left\{ \matrix{
\,\left( {\rm{i}} \right)\,\,a + b = \,9\,\,\,\,\mathop \Rightarrow \limits^{\left( 1 \right)} \,\,\,\,7a = 91\,\,\,\, \Rightarrow \,\,\,\left( {a,b} \right) = \left( {13, - 4} \right)\,\,\,\,{\rm{viable}}!\,\,\,\,\,\,\left[ {\left( 1 \right),\left( 2 \right)\,\,{\rm{ok!}}} \right] \hfill \cr
\,\left( {{\rm{ii}}} \right)\,\,a + b = \, - 7\,\,\,\,\mathop \Rightarrow \limits^{\left( 1 \right)} \,\,\,\, - 9a = 91\,\,\,\, \Rightarrow \,\,\,\left( {a,b} \right) = \left( { - {{91} \over 9},{{28} \over 9}} \right)\,\,\,\,{\rm{viable}}!\,\,\,\,\,\,\left[ {\left( 1 \right),\left( 2 \right)\,\,{\rm{ok!}}} \right] \hfill \cr} \right.$$
We follow the notations and rationale taught in the GMATH method.
Regards,
Fabio.
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