A committee of 6 is chosen from 8 men and 5 women so as to contain at least 2 men and 3 women. How many different committees could be formed?
A. 635
B. 700
C. 1404
D. 2620
E. 3510
The OA is B
Source: Economist GMAT
A committee of 6 is chosen from 8 men and 5 women so as to
This topic has expert replies
GMAT/MBA Expert
- Brent@GMATPrepNow
- GMAT Instructor
- Posts: 16207
- Joined: Mon Dec 08, 2008 6:26 pm
- Location: Vancouver, BC
- Thanked: 5254 times
- Followed by:1268 members
- GMAT Score:770
Since the committee must have 6 people, there are two cases that meet the given restrictions:swerve wrote:A committee of 6 is chosen from 8 men and 5 women so as to contain at least 2 men and 3 women. How many different committees could be formed?
A. 635
B. 700
C. 1404
D. 2620
E. 3510
1) The committee has 2 men and 4 women
2) The committee has 3 men and 3 women
1) The committee has 2 men and 4 women
Since the order in which we select the men and women does not matter, we can use COMBINATIONS
We can select 2 men from 8 men in 8C2 ways (= 28 ways)
We can select 4 women from 5 women in 5C4 ways (= 5 ways)
So, the total number of ways to select 2 men and 4 women = 28 x 5 = 140
2) The committee has 3 men and 3 women
We can select 3 men from 8 men in 8C3 ways (= 56 ways)
We can select 3 women from 5 women in 5C3 ways (= 10 ways)
So, the total number of ways to select 2 men and 4 women = 56 x 10 = 560
So, the TOTAL number of ways to create the 6-person committee = 140 + 560 = 700
Answer: B
Cheers,
Brent
GMAT/MBA Expert
- Scott@TargetTestPrep
- GMAT Instructor
- Posts: 7247
- Joined: Sat Apr 25, 2015 10:56 am
- Location: Los Angeles, CA
- Thanked: 43 times
- Followed by:29 members
swerve wrote:A committee of 6 is chosen from 8 men and 5 women so as to contain at least 2 men and 3 women. How many different committees could be formed?
A. 635
B. 700
C. 1404
D. 2620
E. 3510
The OA is B
Source: Economist GMAT
Since the committee of 6 must contain at least 2 men and 3 women, we can have two scenarios:
1) 2 men and 4 women, or 2) 3 men and 3 women
Scenario 1): 2 men and 4 women.
2 men:
8C2 = (8 x 7)/2! = 28
4 women:
5C4 = 5
The committee of 2 men and 4 women can be selected in 28 x 5 = 140 ways.
Scenario 2): 3 men and 3 women.
3 men:
8C3 = (8 x 7 x 6)/3! = 56
3 women:
5C3 = (5 x 4 x 3)/3! = 10
The committee of 3 men and 3 women can be selected in 56 x 10 = 560 ways
So the total number of ways to select a committee is 140 + 560 = 700.
Answer: B
Scott Woodbury-Stewart
Founder and CEO
[email protected]
See why Target Test Prep is rated 5 out of 5 stars on BEAT the GMAT. Read our reviews
GMAT/MBA Expert
- Scott@TargetTestPrep
- GMAT Instructor
- Posts: 7247
- Joined: Sat Apr 25, 2015 10:56 am
- Location: Los Angeles, CA
- Thanked: 43 times
- Followed by:29 members
swerve wrote:A committee of 6 is chosen from 8 men and 5 women so as to contain at least 2 men and 3 women. How many different committees could be formed?
A. 635
B. 700
C. 1404
D. 2620
E. 3510
The OA is B
Source: Economist GMAT
Since the committee of 6 must contain at least 2 men and 3 women, we can have two scenarios:
1) 2 men and 4 women, or 2) 3 men and 3 women
Scenario 1): 2 men and 4 women.
2 men:
8C2 = (8 x 7)/2! = 28
4 women:
5C4 = 5
The committee of 2 men and 4 women can be selected in 28 x 5 = 140 ways.
Scenario 2): 3 men and 3 women.
3 men:
8C3 = (8 x 7 x 6)/3! = 56
3 women:
5C3 = (5 x 4 x 3)/3! = 10
The committee of 3 men and 3 women can be selected in 56 x 10 = 560 ways
So the total number of ways to select a committee is 140 + 560 = 700.
Answer: B
Scott Woodbury-Stewart
Founder and CEO
[email protected]
See why Target Test Prep is rated 5 out of 5 stars on BEAT the GMAT. Read our reviews