Geometry

As per the figure in the attachment

w=95 degree
z=125 degree

Inside the quardilateral

supplemantary angle of w inside the quardilateral is = 180-95=85 degree

supplemantary angle of w inside the quardilateral is =180-125=55 degree

The angles beside x and y degree inside the quardilateral is (180-x) and (180-y) degree

Since the sum of all the angles inside the quardilateral is 360 degree
we will get the equation as follows

(180-x) + (180-y) + 85 + 55= 360

therefore (x + y) = 140 degree

Whatz the OA?

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beater: Master | Next Rank: 500 Posts; Posts: 301; Joined: Tue Apr 22, 2008 6:07 am; Thanked: 2 times

by beater » Mon Sep 29, 2008 5:41 am

Anyone with a different approach. Thanks!

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4meonly: Legendary Member; Posts: 891; Joined: Sat Aug 16, 2008 4:21 am; Thanked: 27 times; Followed by:1 members; GMAT Score:660(

by 4meonly » Mon Sep 29, 2008 8:13 am

https://www.beatthegmat.com/tough-geomet ... 19549.html

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