Source: Princeton Review
Mixture A is 15 percent alcohol, and mixture B is 50 percent alcohol. If the two are poured together to create a 4-gallon mixture that contains 30 percent alcohol, approximately how many gallons of mixture A are in the mixture?
A. 1.5
B. 1.7
C. 2.3
D. 2.5
E. 3.0
The OA is C
Mixture A is 15 percent alcohol, and mixture B is 50 percent
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Say mixture A is x gallons and mixture B is y gallons.BTGmoderatorLU wrote:Source: Princeton Review
Mixture A is 15 percent alcohol, and mixture B is 50 percent alcohol. If the two are poured together to create a 4-gallon mixture that contains 30 percent alcohol, approximately how many gallons of mixture A are in the mixture?
A. 1.5
B. 1.7
C. 2.3
D. 2.5
E. 3.0
The OA is C
Thus, total amount of alcohol in the combined mixture = 15% of x + 50% of y = 0.15x + 0.5y
Again, the amount of alcohol in the combined mixture = 30% of 4 = 1.2 gallons
Thus, 0.15x + 0.5y = 1.2
We also know that x + y = 4. Tus, y = 4 - x
Plugging-in the value of y = 4 - x in 0.15x + 0.5y = 1.2, we get x = ~2.3
The correct answer: C
Hope this helps!
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Let´s use ALLIGATION, one very useful tool taught in our course!BTGmoderatorLU wrote:Source: Princeton Review
Mixture A is 15 percent alcohol, and mixture B is 50 percent alcohol. If the two are poured together to create a 4-gallon mixture that contains 30 percent alcohol, approximately how many gallons of mixture A are in the mixture?
A. 1.5
B. 1.7
C. 2.3
D. 2.5
E. 3.0
$$?\,\, = x$$
$${x \over 4} = {{50 - 30} \over {50 - 15}} = {4 \over 7}\,\,\,\,\, \Rightarrow \,\,\,\,\,7x = 16\,\,\,\,\, \Rightarrow x = {{14 + 2} \over 7} = 2{2 \over 7}\,\,\,\,\,\,\, \Rightarrow \,\,\,\,\,\left( {\rm{C}} \right)$$
This solution follows the notations and rationale taught in the GMATH method.
Regards,
Fabio.
Fabio Skilnik :: GMATH method creator ( Math for the GMAT)
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Hi All,
We're told that Mixture A is 15 percent alcohol and mixture B is 50 percent alcohol and when a certain amount of each is poured together to create a 4-gallon mixture, the result contains 30 percent alcohol. We're asked approximately how many gallons of mixture A are in the mixture. This "mixture" question can be approached in a number of different ways, including by TESTing THE ANSWERS.
To start, IF we had an EQUAL amount of each Mixture, then the average of the 4-gallon mixture would be (15 + 50)/2 = 65/2 = 32.5% alcohol. This result is TOO HIGH though; the actual mixture is 30%. This means that we'll need a little more of Mixture A... meaning that a little more than 2 gallons (of the 4-gallon total) will be Mixture A. Looking at the answer choices, it's highly likely that the correct answer is Answer C.
We can actually check to see if either Answer C is a match or if Answer D is "too small." We're looking for an answer that would lead to (4)(.3) = 1.2 gallons of alcohol. Answer D is a little 'easier' to work with, so let's TEST that Answer....
Answer D: 2.5 gallons
IF.... we have 2.5 gallons of Mixture A, then we have 4 - 2.5 = 1.5 gallons of Mixture B...
(2.5)(.15) + (1.5)(.5) =
.375 + .75 =
1.125 gallons of Alcohol. This answer is TOO SMALL (we need there to be 1.2 gallons of alcohol). To get more alcohol we need LESS of Mixture A than we have here. There's only one answer that fits...
Final Answer: C
GMAT assassins aren't born, they're made,
Rich
We're told that Mixture A is 15 percent alcohol and mixture B is 50 percent alcohol and when a certain amount of each is poured together to create a 4-gallon mixture, the result contains 30 percent alcohol. We're asked approximately how many gallons of mixture A are in the mixture. This "mixture" question can be approached in a number of different ways, including by TESTing THE ANSWERS.
To start, IF we had an EQUAL amount of each Mixture, then the average of the 4-gallon mixture would be (15 + 50)/2 = 65/2 = 32.5% alcohol. This result is TOO HIGH though; the actual mixture is 30%. This means that we'll need a little more of Mixture A... meaning that a little more than 2 gallons (of the 4-gallon total) will be Mixture A. Looking at the answer choices, it's highly likely that the correct answer is Answer C.
We can actually check to see if either Answer C is a match or if Answer D is "too small." We're looking for an answer that would lead to (4)(.3) = 1.2 gallons of alcohol. Answer D is a little 'easier' to work with, so let's TEST that Answer....
Answer D: 2.5 gallons
IF.... we have 2.5 gallons of Mixture A, then we have 4 - 2.5 = 1.5 gallons of Mixture B...
(2.5)(.15) + (1.5)(.5) =
.375 + .75 =
1.125 gallons of Alcohol. This answer is TOO SMALL (we need there to be 1.2 gallons of alcohol). To get more alcohol we need LESS of Mixture A than we have here. There's only one answer that fits...
Final Answer: C
GMAT assassins aren't born, they're made,
Rich
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We let a = the number of gallons of mixture A and b = the number of gallons of mixture B. We can create the equations:BTGmoderatorLU wrote:Source: Princeton Review
Mixture A is 15 percent alcohol, and mixture B is 50 percent alcohol. If the two are poured together to create a 4-gallon mixture that contains 30 percent alcohol, approximately how many gallons of mixture A are in the mixture?
A. 1.5
B. 1.7
C. 2.3
D. 2.5
E. 3.0
a + b = 4
b = 4 - a
and
0.15a + 0.5b = 0.3(a + b)
15a + 50b = 30a + 30b
20b = 15a
4b = 3a
Substituting we have:
4(4 - a) = 3a
16 - 4a = 3a
16 = 7a
a = 16/7 ≈ 2.3
Answer: C
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