[Math Revolution GMAT math practice question]
Is x/y < 0?
1) x^4y^5 < 0
2) x^5y^3 < 0
Is x/y < 0?
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- Max@Math Revolution
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Target question: Is x/y < 0?Max@Math Revolution wrote:Is x/y < 0?
1) (x^4)(y^5) < 0
2) (x^5)(y^3) < 0
Statement 1: (x^4)(y^5) < 0
There are several values of x and y that satisfy statement 1. Here are two:
Case a: x = 1 and y = -1. Notice that (x^4)(y^5) = (1^4)(-1^5) = (1)(-1) = -1, which is less than 0. In this case, x/y = 1/(-1) = -1. So, the answer to the target question is YES, x/y IS less than 0
Case b: x = -1 and y = -1. Notice that (x^4)(y^5) = (-1^4)(-1^5) = (1)(-1) = -1, which is less than 0. In this case, x/y = -1/(-1) = 1. So, the answer to the target question is NO, x/y is NOT less than 0
Since we cannot answer the target question with certainty, statement 1 is NOT SUFFICIENT
Statement 2: (x^5)(y^3) < 0
Since x^4 is POSITIVE, we can safely divide both sides of the inequality by x^4 to get: (x)(y^3) < 0
Since y^4 is POSITIVE, we can safely divide both sides of the inequality by y^4 to get: x/y < 0
So, the answer to the target question is YES, x/y IS less than 0
Since we can answer the target question with certainty, statement 2 is SUFFICIENT
Answer: B
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Is x/y < 0?
1) x^4*y^5 < 0
As x^4 is always positive, it implies y < 0
if x > 0
then x/y < 0
if x < 0, then x/y > 0
Insufficient
2) x^5*y^3 < 0
As X,Y are both having the odd power, they retain their sign, and
Since the product is positive , both the variables have same sign
Positive * positive = positive
negative*negative = positive
So, x/y will be greater than zero as sign cancels out
Sufficient
Option B is correct
1) x^4*y^5 < 0
As x^4 is always positive, it implies y < 0
if x > 0
then x/y < 0
if x < 0, then x/y > 0
Insufficient
2) x^5*y^3 < 0
As X,Y are both having the odd power, they retain their sign, and
Since the product is positive , both the variables have same sign
Positive * positive = positive
negative*negative = positive
So, x/y will be greater than zero as sign cancels out
Sufficient
Option B is correct
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$$\frac{x}{y}\,\,\mathop < \limits^? \,\,0$$Max@Math Revolution wrote:[Math Revolution GMAT math practice question]
Is x/y < 0?
1) x^4y^5 < 0
2) x^5y^3 < 0
$$\left( 1 \right)\,\,{x^4}{y^5} < 0\,\,\,\,\,\, \Rightarrow \,\,\,\,\,\,x \ne 0\,\,\,{\rm{and}}\,\,\,y < 0\,\,\,\,\,\,\left\{ \matrix{
\,{\rm{Take}}\,\,\left( {x,y} \right) = \left( {1, - 1} \right)\,\,\,\,\, \Rightarrow \,\,\,\,\,\left\langle {{\rm{YES}}} \right\rangle \,\, \hfill \cr
\,{\rm{Take}}\,\,\left( {x,y} \right) = \left( { - 1, - 1} \right)\,\,\,\,\, \Rightarrow \,\,\,\,\,\left\langle {{\rm{NO}}} \right\rangle \,\, \hfill \cr} \right.$$
$$\left( 2 \right)\,\,{x^5}{y^3} < 0\,\,\,\,\,\, \Rightarrow \,\,\,\,\,\left\{ \matrix{
\,x > 0\,\,\,{\rm{and}}\,\,\,y < 0\,\,\,\,\, \Rightarrow \,\,\,\,\,\left\langle {{\rm{YES}}} \right\rangle \hfill \cr
\,{\rm{or}} \hfill \cr
\,x < 0\,\,\,{\rm{and}}\,\,\,y > 0\,\,\,\,\, \Rightarrow \,\,\,\,\,\left\langle {{\rm{YES}}} \right\rangle \hfill \cr} \right.\,\,\,\,\,\,\,\,\,\,\, \Rightarrow \,\,\,\,\,\,\,\left\langle {{\rm{YES}}} \right\rangle $$
This solution follows the notations and rationale taught in the GMATH method.
Regards,
Fabio.
Fabio Skilnik :: GMATH method creator ( Math for the GMAT)
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- Max@Math Revolution
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=>
Forget conventional ways of solving math questions. For DS problems, the VA (Variable Approach) method is the quickest and easiest way to find the answer without actually solving the problem. Remember that equal numbers of variables and independent equations ensure a solution.
The question is equivalent to asking if xy < 0. This can be seen by multiplying both sides of the inequality by y^2.
Since we can ignore even exponents in inequalities like x^4y^5 < 0, condition 1) is equivalent to the statement y < 0 and condition 2) is equivalent to the statement xy < 0.
Therefore, the answer is B.
Answer: B
Forget conventional ways of solving math questions. For DS problems, the VA (Variable Approach) method is the quickest and easiest way to find the answer without actually solving the problem. Remember that equal numbers of variables and independent equations ensure a solution.
The question is equivalent to asking if xy < 0. This can be seen by multiplying both sides of the inequality by y^2.
Since we can ignore even exponents in inequalities like x^4y^5 < 0, condition 1) is equivalent to the statement y < 0 and condition 2) is equivalent to the statement xy < 0.
Therefore, the answer is B.
Answer: B
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