Is x + y > 0 ? (1) x - y > 0 (2) x^2 - y^2 > 0

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Is x + y > 0 ?

(1) x - y > 0
(2) x^2 - y^2 > 0

OA C

Source: Manhattan Prep

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by Jay@ManhattanReview » Sat Dec 29, 2018 2:11 am

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BTGmoderatorDC wrote:Is x + y > 0 ?

(1) x - y > 0
(2) x^2 - y^2 > 0

OA C

Source: Manhattan Prep
We have to determine whether x + y > 0.

Let's take each statement one by one.

(1) x - y > 0

Case 1: Say x = 3 and y = 2, then x - y > 0 and x + y = 5 and x + y > 0. The answer is Yes.
Case 2: Say x = -2 and y = -3, then x - y > 0 => -2 + 3 = 1 > 0 and x + y = -5 and x + y < 0. The answer is No. Insufficient.

(2) x^2 - y^2 > 0

Case 1: Say x = 3 and y = 2, then x^2 - y^2 > 0 and x + y = 5 and x + y > 0. The answer is Yes.
Case 2: Say x = -3 and y = -2, then x^2 - y^2 > 0 and x + y = -5 and x + y < 0. The answer is No. Insufficient.

(1) and (2) together

Since from (1), we have x > y, Case 2 from Statement 2 is invalid. Thus, only Case 1 is valid. Thus, the answer is Yes. Sufficient.

The correct answer: C

Hope this helps!

-Jay
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by fskilnik@GMATH » Sat Dec 29, 2018 5:23 pm

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BTGmoderatorDC wrote:Is x + y > 0 ?

(1) x - y > 0
(2) x^2 - y^2 > 0
Source: Manhattan Prep
$$x + y\,\,\mathop > \limits^? \,\,0$$
$$\left( 1 \right)\,\,x > y\,\,\,\left\{ \matrix{
\,{\rm{Take}}\,\,\left( {x,y} \right) = \left( {1,0} \right)\,\,\,\, \Rightarrow \,\,\,\,\left\langle {{\rm{YES}}} \right\rangle \hfill \cr
\,{\rm{Take}}\,\,\left( {x,y} \right) = \left( {0, - 1} \right)\,\,\,\, \Rightarrow \,\,\,\,\left\langle {{\rm{NO}}} \right\rangle \hfill \cr} \right.$$
$$\left( 2 \right)\,\,\left| x \right| > \left| y \right|\,\,\,\left\{ \matrix{
\,\left( {{\mathop{\rm Re}\nolimits} } \right){\rm{Take}}\,\,\left( {x,y} \right) = \left( {1,0} \right)\,\,\,\, \Rightarrow \,\,\,\,\left\langle {{\rm{YES}}} \right\rangle \hfill \cr
\,{\rm{Take}}\,\,\left( {x,y} \right) = \left( { - 1,0} \right)\,\,\,\, \Rightarrow \,\,\,\,\left\langle {{\rm{NO}}} \right\rangle \hfill \cr} \right.$$
$$\left( {1 + 2} \right)\,\,\left\{ \matrix{
\,\left( 1 \right)\,\,\,x - y > 0 \hfill \cr
\,\left( 2 \right)\,\,\, \Rightarrow \,\,\,\left( {x + y} \right)\left( {x - y} \right) > 0 \hfill \cr} \right.\,\,\,\,\,\,\, \Rightarrow \,\,\,\,\,\,\,x + y > 0\,\,\,\, \Rightarrow \,\,\,\,\left\langle {{\rm{YES}}} \right\rangle $$

This solution follows the notations and rationale taught in the GMATH method.

Regards,
Fabio.
Fabio Skilnik :: GMATH method creator ( Math for the GMAT)
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