Source: Veritas Prep
Which of the following is NOT a point on the circle of radius 5 and center O as graphed above?
A. (-1, 2)
B. (8, -1)
C. (0, -5)
D. (6, 3)
E. (7, -6)
The OA is E.
Which of the following is NOT a point on the circle of
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- Jay@ManhattanReview
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Distance formula:
Note that distance between two points whose coordinates are (x, y) and (a, b) is given by
= √[(x - a)^2 + (y - b)^2]
The point whose coordinates are (x, y) is on the circle and the point whose coordinates are (a, b) is the center of the circle, thus, a = 3 and b = - 1.
Thus, Radius = √[(x - a)^2 + (y - b)^2] = √[(x - 3)^2 + (y + 1)^2]
5 = √[(x - 3)^2 + (y + 1)^2]
25 = (x - 3)^2 + (y + 1)^2
You may lug-in option values and check which one fits. You'll find that option E: (7, -6) is NOT on the circle.
Let's see:
Option E: (7, -6)
(7 - 3)^2 + (-6 + 1)^2 = 16 + 25 = 41 ≠25.
The correct answer: E
Hope this helps!
-Jay
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- fskilnik@GMATH
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Let´s translate the x axis 1 unit down ("y" goes "y+1") and the y axis 3 units to the right ("x" goes "x-3").
Doing so, the center of the circle given is now at the origin(!) and "extremal points" are re-coordenated as shown:
(A) (-1,2) goes to (-4,3)
(B) (8,-1) goes to (5, 0)
(C) (0,-5) goes to (-3, -4)
(D) (6,3) goes to (3,4)
(E) (7, -6) goes to (4, -5)
It is clear that point (4,-5) does not belong to the given circle!
(It is also clear that all other points are on the circumference of the given circle... think about 3,4,5!)
This solution follows the notations and rationale taught in the GMATH method.
Regards,
Fabio.
Fabio Skilnik :: GMATH method creator ( Math for the GMAT)
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