In a right triangle, the longer leg is two more than three

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Magoosh

In a right triangle, the longer leg is two more than three times the shorter leg, and the area of the triangle is 400. What is the length of the shorter leg?

A. 16
B. 20
C. 25
D. 32
E. 40

OA A

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by GMATGuruNY » Sat Oct 27, 2018 6:05 am
AAPL wrote:Magoosh

In a right triangle, the longer leg is two more than three times the shorter leg, and the area of the triangle is 400. What is the length of the shorter leg?

A. 16
B. 20
C. 25
D. 32
E. 40
We can PLUG IN THE ANSWERS, which represent the length of the shorter leg.
When the correct answer is plugged in, the area = 400.

B: 20
Longer leg = two more than three times the shorter leg = 2 + 3*20 = 62.
Area = (1/2)(20)(62) = 620.
Since the area is too great, a smaller answer choice is needed.

The correct answer is A.
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by Brent@GMATPrepNow » Sat Oct 27, 2018 7:05 am
AAPL wrote:MagooshIn a right triangle, the longer leg is two more than three times the shorter leg, and the area of the triangle is 400. What is the length of the shorter leg?
A. 16
B. 20
C. 25
D. 32
E. 40
OA A
In a right triangle, the longest side is called the hypotenuse, and the two sides that meet to create a 90-degree angle are called the legs.
So, one leg will be the triangle's base, and the other leg will be the triangle's height.

Let x = length of the triangle's base (which, for this question, will be the SHORTER leg)

The longer leg is two more than three times the shorter leg
If x = length of shorter leg (aka the base), then...
3x + 2 = length of longer leg (aka the height)

The area of the triangle is 400. What is the length of the shorter leg?
Area of triangle = (base)(height)/2

We can write: (x)(3x + 2)/2 = 400
Multiply both sides by 2 to get: (x)(3x + 2) = 800
Expand left side: 3x² + 2x = 800
Set equal to zero to get: 3x² + 2x - 800 = 0
Hmmm, I don't want to solve this awful quadratic equation, so what can I do?

One option is to start plugging in each answer choice to see which one satisfies the equation, but that could take a while.

Another thing we might do is recognize that, if (x)(3x + 2) = 800 (an earlier equation we derived), and if x is an integer (which we know is true, given the answer choices), then it's quite likely that x and (3x+2) are both divisors of 800

So, for each answer choice (possible x-value), we might first test whether (3x+2) is a divisor of 800.
For example, if x = 20 (answer choice B) then 3x + 2 = 3(20) +2 = 62
Since 62 is NOT a divisor of 800, we might check another answer choice.

With this strategy, we can see that, if x = 16 (answer choice A) then 3x + 2 = 3(16) +2 = 50
Since 50 IS a divisor of 800, we might check to see whether this value of x satisfies the equation (x)(3x + 2) = 800
When x = 16, we get: (16)(50) = 800 PERFECT!!

Answer: A

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Brent
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