For integers m and n, the operation â–³ is defined by mâ–³n

This topic has expert replies
User avatar
Elite Legendary Member
Posts: 3991
Joined: Fri Jul 24, 2015 2:28 am
Location: Las Vegas, USA
Thanked: 19 times
Followed by:37 members

Timer

00:00

Your Answer

A

B

C

D

E

Global Stats

[Math Revolution GMAT math practice question]

For integers m and n, the operation $$\triangle$$ is defined by
$$m\ \triangle\ n\ =\ \left(m-1\right)^2+\left(n+1\right)^2$$
What is the value of the integer x?

$$\left(1\right)\ x\triangle1\ =4$$
$$\left(2\right)\ 1\triangle x=4$$

User avatar
GMAT Instructor
Posts: 1449
Joined: Sat Oct 09, 2010 2:16 pm
Thanked: 59 times
Followed by:33 members

by fskilnik@GMATH » Wed Oct 24, 2018 12:57 pm

Timer

00:00

Your Answer

A

B

C

D

E

Global Stats

Max@Math Revolution wrote:[Math Revolution GMAT math practice question]

For any integers m and n,
$$m\ \triangle\ n\ =\ \left(m-1\right)^2+\left(n+1\right)^2$$
What is the value of the integer x?

$$\left(1\right)\ x\triangle1\ =4$$
$$\left(2\right)\ 1\triangle x=4$$
$$m\ \triangle\ n\ =\ \left(m-1\right)^2+\left(n+1\right)^2 \,\,\,\,\,\left[ {m,n\,\,{\rm{ints}}} \right]$$
$$? = x\,\,\,\,\,\,\left[ {\,x\,\,{\mathop{\rm int}} \,} \right]$$
$$\left( 1 \right)\,\,\,4 = x\,\vartriangle \:1\,\, = \,\,{\left( {x - 1} \right)^2} + {\left( {1 + 1} \right)^2}\,\,\,\,\, \Rightarrow \,\,\,\,\,{\left( {x - 1} \right)^2} = 0\,\,\,\,\,\, \Rightarrow \,\,\,\,\,\,x = 1\,\,\,\,\,\,\, \Rightarrow \,\,\,\,\,\,{\text{SUFF}}.\:$$
$$\left( 2 \right)\,\,\,4 = 1\,\vartriangle \: x\,\, = \,\,{\left( {1 - 1} \right)^2} + {\left( {x + 1} \right)^2}\,\,\,\,\, \Rightarrow \,\,\,\,\,{\left( {x + 1} \right)^2} = 4\,\,\,\,\,\, \Rightarrow \,\,\,\,\,\,x = 1\,\,\,{\text{or}}\,\,\,x = - 3\,\,\,\,\,\,\, \Rightarrow \,\,\,\,\,\,\,{\text{INSUFF}}.\:$$

This solution follows the notations and rationale taught in the GMATH method.

Regards,
Fabio.
Fabio Skilnik :: GMATH method creator ( Math for the GMAT)
English-speakers :: https://www.gmath.net
Portuguese-speakers :: https://www.gmath.com.br

User avatar
Elite Legendary Member
Posts: 3991
Joined: Fri Jul 24, 2015 2:28 am
Location: Las Vegas, USA
Thanked: 19 times
Followed by:37 members

by Max@Math Revolution » Thu Oct 25, 2018 11:44 pm

Timer

00:00

Your Answer

A

B

C

D

E

Global Stats

=>

Forget conventional ways of solving math questions. For DS problems, the VA (Variable Approach) method is the quickest and easiest way to find the answer without actually solving the problem. Remember that equal numbers of variables and independent equations ensure a solution.

Since we have 1 variable (x) and 0 equations, D is most likely to be the answer. So, we should consider each of the conditions on their own first.

Condition 1)
$$x\ \triangle\ 1\ =\left(x-1\right)^2+\left(1+1\right)^2=\left(x-1\right)^2+2^2=4$$
Thus, (x-1)^2 = 0 and x = 1.
Since we have a unique solution, condition 1) is sufficient.

Condition 2)
$$1\ \triangle\ x=\left(1-1\right)^2+\left(x+1\right)^2=\left(x+1\right)^2=4$$
So, x+1 = ±2 or x = -1 ± 2.
Thus, x = -3 or x = 1.
Since we don't have a unique solution, condition 2) is not sufficient.

Therefore, A is the answer.
Answer: A

If the original condition includes "1 variable", or "2 variables and 1 equation", or "3 variables and 2 equations" etc., one more equation is required to answer the question. If each of conditions 1) and 2) provide an additional equation, there is a 59% chance that D is the answer, a 38% chance that A or B is the answer, and a 3% chance that the answer is C or E. Thus, answer D (conditions 1) and 2), when applied separately, are sufficient to answer the question) is most likely, but there may be cases where the answer is A,B,C or E.